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4 years ago

11

The average daily temperature in Denton went from –8°F in January to 43°F in March. What was the change in average daily tempera

ture from January to March?

1 answer:

11111nata11111 [884]4 years ago

7 0

Answer:

8

Step-by-step explanation:

You might be interested in

if there are four trucks parked in line and after the first truck each truck weighed 2 more tons than the one before. They all w

algol13

Each truck weighs five tons.

1st truck: n
2nd truck: n + 2
3rd truck: n + 4
4th truck: n + 6

n + n + 2 + n + 4 + n + 6 = 32
4n + 12 = 32
- 12 - 12
--------------------
4n = 20
---- ------
4 4

n = 5

6 0

4 years ago

Yeahhh i just wanna get this over with so i can go to sleep

jeka94

Answer:

the answer to this question is 11

3 0

2 years ago

56. Kelly found that the length of the hypotenuse of a triangle was equal to the square root of 125. The length of the hypotenus

Karo-lina-s [1.5K]

Answer: B: 11 and 12

Step-by-step explanation:

- An integer is simply a whole number

- So consecutive integers are simply whole numbers that follow each other (ex: 1, 2, 3)

- The square root of 125 (in decimals) is 11.1803398875, meaning it is higher than 11 but less than 12

- So 11.1803398875 falls between 11 and 12, making the answer B

hope this helps :)

3 0

2 years ago

Solve 5x + 4/y =7 and 4x + x/y =5 simultaneously.

Nuetrik [128]

9514 1404 393

Answer:

(x, y) ≈ (1.1642, 3.3930) and (3.4358, -0.39297)

Step-by-step explanation:

Solve the first equation for y, then substitute into the second.

5x +4/y = 7

4/y = 7 -5x

4/(7 -5x) = y

Then the second equation becomes ...

4x +x/(4/(7 -5x)) = 5

4x +x(7 -5x)/4 = 5

16x +7x -5x^2 = 20 . . . . . multiply by 4

5x^2 -23x +20 = 0 . . . . . put in standard form

We can use the quadratic formula to solve this.

x = (23±√((-23)² -4(5)(20)))/(2(5)) = (23±√129)/10

x = 2.3 ±√1.29 ≈ {1.1642, 3.4358}

y = 4/(7 -5x) = {3.3930, -0.39297}

Solutions are (x, y) ≈ (1.1642, 3.3930) and (3.4358, -0.39297).

5 0

4 years ago

Find the EXACT solution to the exponential equation 500=20(1.5)^(4x)

tangare [24]

$500=20(1.5)^{4x}\implies \cfrac{500}{20}=1.5^{4x}\implies 25=1.5^{4x}
\\\\\\
\textit{now, we'll take a common log, any will do, we'll use ln()}
\\\\\\
ln(25)=ln\left(1.5^{4x} \right)\\\\
-----------------------------\\\\
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\
-----------------------------\\\\
thus\implies ln(25)=4xln(1.5)\implies \cfrac{ln(25)}{4ln(1.5)}=x$

6 0

4 years ago