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IrinaVladis [17]
3 years ago
6

On a morning in December, Carl wakes up and checks the thermometer. He reads that it is -10°F. In two hours he checks and the te

mperature has risen 4°F. In another three hours the temperature has risen 7°F. At the last time, he checks the thermometer, what is the temperature? Also writes an addition equation that models this situation​
Mathematics
2 answers:
bulgar [2K]3 years ago
5 0

Answer: 1 degree Fahrenheit

Step-by-step explanation:

The temperature starts at -10 degrees F, so if in two hours, the temperature has risen by 4 degrees, then the new temperature is -10 + 4 = -6 degrees F. 3 hours later, the temperature has risen another 7 degrees, so the new temperature is -6 + 7 = 1 degrees F. "addition equation" is ambiguous without knowing what class you are taking, but one such equation to represent the situation could be T = -10 + 4 + 7 = 1.

sasho [114]3 years ago
3 0

Answer:

1°F            -10+4+7=1

Step-by-step explanation:

PLZ MARK ME BRAINLYIST

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4 0
3 years ago
Find the perimeter of the figure
nalin [4]

Answer:

The perimeter is 66.9 units

Step-by-step explanation:

See the attached figure with letters to better understand the problem

step 1

In the right triangle ABD

<em>Find the length side AD</em>

tan(33^o)=\frac{8}{AD} ----> by TOA (opposite side divided by the adjacent side)

AD=\frac{8}{tan(33^o)}=12.3\ units

Find the length side BD

sin(33^o)=\frac{8}{BD} ---> by SOH (opposite side divided by the hypotenuse)

BD=\frac{8}{sin(33^o)}=14.7\ units

step 2

In the right triangle CDE

Find the length side CE

cos(64^o)=\frac{CD}{CE} --> by CAH (adjacent side divided by the hypotenuse)

we have

CD=BD/2=14.7/2=7.35\ units

substitute

CE=\frac{7.35}{cos(64^o)}=16.8\ units

Find the length side DE

tan(64^o)=\frac{DE}{CD} --> by TOA (opposite side divided by the adjacent side)

DE=tan(64^o){7.35}=15.1\ units

step 3

Find the perimeter of the figure

The perimeter is equal to

P=AB+AD+BD+CE+DE

substitute the values

P=8+12.3+14.7+16.8+15.1=66.9\ units

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3 years ago
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