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e-lub [12.9K]
2 years ago
8

I need someone to explain what I did wrong

Mathematics
1 answer:
egoroff_w [7]2 years ago
4 0

Answer:

g(f(4)) = 9

Step-by-step explanation:

Fill in gf(x) for where x is in g(x): (x-7)²

Then, fill in 4 for where x is: (4-7)²

Square it: (-3)²

9

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sergey [27]
Probability that carbon essissions beyond permissible level and test predicts did it
5 0
3 years ago
Giving brainliest!!!
hjlf

Answer:

1/16

Step-by-step explanation:

1/8 × 1/2

multiply the numerator= 1

multiply the denominator= 16

that is

1/16

3 0
2 years ago
What is the slope of the line that passes through the points (-1, 2) and (-4, 3)?
Rus_ich [418]

Answer: -1/3

Step-by-step explanation:

Slope is the difference between the y coordinate points divided by the x coordinate points

We have (-1, 2) and (-4, 3)

Slope = 3 - 2/ -4 - (-1)

Slope = -1/3

5 0
2 years ago
pllz answer Masterson Wood Products pays Patricia Griffin a $640 monthly salary plus a 11% commission on merchandise she sells e
Marianna [84]

Answer:

$8659

Step-by-step explanation:

Patricia's sales = $ 72,900

Her commission = 11% of $72,900

= 11/100 * 72,900 [ % means out of 100 and of means to multiply ]

= 11 * 729

= $ 8019

Her monthly salary = $640

Her monthly salary along with commission = $640 + $8019

= $8659

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
3 0
2 years ago
Read 2 more answers
Sketch the region enclosed by y=3x and y=x^2 . Then find the area of the region.
kolezko [41]

Answer:

A=4.5u^2

Step-by-step explanation:

The integral of a function gives you the area under the curve, the subtraction of one of the areas from the other will give you the area in between.

The limits of integration are the points where the curves intersect each other(take the curves has a system of equation and solve for x and y):

y=3x, y=x^2\\3x=x^2\\x^2-3x=0\\x(x-3)=0\\x_1=0\\x-3=0\\x_2=3

y_1=3x_1=3(0)=0\\y_2=3x_2=3(3)=9

The integral will be the subtraction of the curve y=3x and y=x^2  (In the graph you can see y=3x is the upper curve):

\int\limits^3_0 {3x-x^2} \, dx =\left\frac{3x^2}{2}-\frac{x^3}{3}\right|^3_0=\frac{3(3)^2}{2}-\frac{(3)^3}{3}-\left(\frac{3(0)^2}{2}-\frac{(0)^3}{3}\right)\\\int\limits^3_0 {3x-x^2} \, dx =\frac{27}{2}-\frac{27}{3} =13.5-9=4.5u^2

6 0
2 years ago
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