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2 years ago

8

I need someone to explain what I did wrong

1 answer:

egoroff_w [7]2 years ago

4 0

Answer:

g(f(4)) = 9

Step-by-step explanation:

Fill in gf(x) for where x is in g(x): (x-7)²

Then, fill in 4 for where x is: (4-7)²

Square it: (-3)²

9

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<img src="https://tex.z-dn.net/?f=%5Csqrt25" id="TexFormula1" title="\sqrt25" alt="\sqrt25" align="absmiddle" class="latex-formu

anzhelika [568]

Answer:

Rational

Step-by-step explanation:

The square root of 25 is 5, which is a rational number.

4 0

2 years ago

Read 2 more answers

8. The area of the bigger square at the picture is 32. What is the area of

Karolina [17]

Answer:

16 is the awnser or at least I belive

8 0

2 years ago

Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$

Length between $P_1$ and $P_{2}$ , (Side 1) :

$(x_1, y_1) = (- 1, 4)$ and

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2$

$= \sqrt{7^2 + 2^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}}$

Length of Side 1 = $\sqrt{\textbf{53}}$ units.

Distance between $P_1$ and $P_2$ , (Side 2):

$(x_1, y_1) = (-1, 4)$

$(x_2, y_2) = (4, - 5)$

Distance = $\sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2$

$= \sqrt{ 25 + 81 }$

$= \sqrt{\textbf{106}}$

Length of Side 2 = $\sqrt{\textbf{106}}$ units.

Distance between $P_2$ and $P_3$ , Side 3 :

$(x_1, y_1) = (4, 5)$

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}$

Length of Side 3 = $\sqrt{\textbf{53}}$ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$\bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2$

i.e, 53 + 53 = 106

Hence, the triangle is a right - angled triangle as well.

7 0

3 years ago

Which of the following graphs would you use if you wanted viewers to see individual data points?

Arturiano [62]

I would either use a histogram or a frequency chart, but histogram is easier and neater

7 0

2 years ago

X= -2 / Y= -4 / Z= 4<br><br> (1.-) 3x + z - y<br><br> (2.-) 2xz - 3xy + 4<br><br><br> Pls help me!

Sergio [31]

Answer:

1.-3x+z - y

-3(-2)+4-(-4)

6+4+4

=14.

2.-2xz-3xy+4

-2(-2(4))-3(-2(-4))

-2(-8)-3(8)

16-24

= -8.

4 0

3 years ago