Ask question

Ask question

All categories

2 years ago

11

In the playing card deck below what is the chance of pulling 2 face cards without replacing the cards in between pulls? Answer i

n decimal form rounded to the 6th digit after the decimal

1 answer:

Annette [7]2 years ago

8 0

Answer:

.049774

12/52 x 11/51 = .04977376

You might be interested in

Can someone help me and explain? I will mark brainlest. ♡

Sedbober [7]

Answer:

$p'(4) = -3$

$q'(8) = \frac{1}{4}\\$

Step-by-step explanation:

For p'(4):

$p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)$

$p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3$

For q'(8):

$q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}$

$q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}$

4 0

2 years ago

Read 2 more answers

3 equivalent ratios for 20/15

castortr0y [4]

4/3
40/30
60/45
Simply multiply or divide both the 20 and the 15 to get an equivalent ratio.

7 0

2 years ago

Read 2 more answers

Read each of the statements that describe possible decompositions of the polygon in the image into two triangles that can repres

jasenka [17]

Need more information

4 0

2 years ago

Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0

Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . $x^{2}e^{-x}+2y^{2}-xy$ "

Answer : $\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

Step-by-step explanation:

From the expression $x^{2}e^{-x}+2y^{2}-xy$ " y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

$\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\$

for the expression $\frac{d}{dx}(x^{2}e^{-x})$ we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

$(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\$ .

if we make dy/dx subject of formula we arrive at

$(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

5 0

3 years ago

Let u = <-9, 4>, v = <8, -5>. Find u - v. <br> URGENT

Pie

To subtract vectors, you simply have to subtract correspondent coordinates.

So, if you have

$u = \langle u_1,\ u_2,\ldots u_n\rangle ,\quad v = \langle v_1,\ v_2,\ldots v_n\rangle$

the subtraction is simply

$u-v = \langle u_1-v_1,\ u_2-v_2,\ldots u_n-v_n\rangle$

So, in your case, we have

$\langle-9,4\rangle-\langle 8,-5\rangle=\langle -9-8, 4+5\rangle=\langle -17,9\rangle$

3 0

2 years ago