Answer:
Bag 1: 20
Bag 2: 40
Step-by-step explanation:
Let x be the amount taken out of bag 2
Then the amount left in each bag can be written as:
Bag 1: 50-3x
Bag 2: 50-x
Since we know that half of bag 2 is bag 1, that gives us:
50-3x = 1/2(50-x)
-> 50-3x = 25-x/2
Now lets isolate x and solve:
25 = 5x/2
-> 50 = 5x
-> x = 10
So plug x bag in for the original equations:
Bag 1: 50-3x = 50-3(10) = 20
Bag 2: 50-x = 50-10 = 40
RQ² = RP² + PQ²
RQ² = 45² + 24²
RQ² = 2025 + 576
RQ² = 2601
RQ = 51
PT/PR = PQ/RQ
PT/45 = 24/51
PT = (24/51) × 45
PT = (8/17) × 45
PT = 360/17
d
4x - 9x + 11 = -24
-5x + 11 = - 24
-5x = -24 - 11
-5x = -35
-5x/-5 = -35/-5
x = 7
97
83 and JKL form a straight line so they add to 180 degrees
83+ JKL = 180
Subtract 180 from each side
83-83+ JKL = 180-83
JKL = 97