4 years ago

X^2-8x+5=0 Solve by completing the square.

1 answer:

8 0

$x^2-8x+5=0 \\
x^2-8x+16-11=0\\
(x-4)^2=11\\
x-4=-\sqrt{11} \vee x-4=\sqrt{11}\\
x=4-\sqrt{11} \vee x=4+\sqrt{11}\\$

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