Question

Can I get help on 1,2 and 5?

Answer 1

1. Is x=4
2. Is x=7
Those should be the correct answers for those questions

Answer 2

Answer:

Question 1: $x=4$

Question 2: $x= \pm7$

Question 5: The dimensions of one face of the container are 6 by 6 inches.

Step-by-step explanation:

Hi there!

Question 1

$x^3=64$

Rewrite 64 as a power of 3:

$x^3=4^3$

(We could find that 4³ = 64 through trial and error)

This above equation makes it true that x=4. If aⁿ = bⁿ, then a=b:

$x=4$

Question 2

$x^2=49$

Rewrite 49 as a power of 2:

$x^2=7^2$

Again, we could have found this through trial and error, or by looking at our multiplication tables.

$x=7$

However, remember that positive and negative numbers will all square to be a positive number. So, therefore, x can be -7 OR 7 (since both, when squared, equal 49):

$x= \pm7$

Question 5

Let x be equal to the length of one edge of the cube.

Volume of a cube formula: $V=x^3$

Plug in the given information, when V is the volume:

$216=x^3$

Rewrite 216 as a power of 3:

$6^3=x^3$

^ We could have found this through trial and error.

$x=6$

Therefore, the dimensions of one face of the container are 6 by 6 inches.

I hope this helps!