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muminat
3 years ago
5

What is the value of the underlined digit? 587

Mathematics
2 answers:
Nadya [2.5K]3 years ago
8 0
There is no underlined dogit
Murljashka [212]3 years ago
4 0
If the line is under the 5 it's five hundreds, in the 8 eight hundreds, and the 7 seven ones.
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You work at a T-shirt printing business. Of 1,300 T-shirts shipped, 106 are imperfect. If you choose a T-shirt at random from th
Colt1911 [192]

It is given in the question that

You work at a T-shirt printing business. Of 1,300 T-shirts shipped, 106 are imperfect.

So out  of 1300 T-shirts, number of perfect t-shirts are

1300-106=1194

So probability that the t-shirt is printed correctly is

= \frac{1194}{1300}=0.92

And to find the percentage, we have to multiply it by 100, and on doing so we will get 92 % .

5 0
3 years ago
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OMG PLSS ANSWERR People use water to​ cook, clean, and drink every day. An estimate of 17.2% of the water used each day is for c
Anna71 [15]

Answer:

260 gallons

Step-by-step explanation:

Hope it's correct

8 0
3 years ago
Which statement best reflects the solution(s) of the equation?
Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation \frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1} and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0

Now, factoring the term:

x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, \frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}  the denominator becomes zero i.e

\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2  in the equation,

\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}

\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

  • brainly.com/question/1626495
  • brainly.com/question/2959656
  • brainly.com/question/2456302

#learnwithBrainly

5 0
3 years ago
WILL MARK BRAINLIST!!!!!!!!!!<br> |a+x|/ 2 − |a−x|/ 2 if a=−2; x=−6
blagie [28]
If those lines are absolute value then the answer is 0 if they are supposed to be parenthesis then the answer is -6
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3 years ago
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A=1,200×(1−0.25)^(3)
A=506.25
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