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2 years ago

Convert 3.5 ⋅ 10^4 to standard form. A. 35,000 B. 3,500 C. 0.00035 D. 0.000035

Mathematics

2 answers:

ruslelena [56]2 years ago

7 0

A. move the decimal place to the right 4 times

Maru [420]2 years ago

6 0

Answer:

Step-by-step explanation:

answer is B, 3,500. B 3500

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WILL GIVE BRAINLIEST

padilas [110]

Okay so first do 2x3 which equals 6. then add 6 to 1 and you would get 7. so 7/2 is your answer!!

denominator- bottom half of a fraction ex. in the fraction 5/7 the bottom number (7) is the denominator

numerator- top half of a fraction ex. in 5/7 the top (5) is the numerator

whole number-a number without fractions ex. 7, 29, 18

8 0

2 years ago

Read 2 more answers

Solve the Anti derivative.

Alex Ar [27]

Answer:

$\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C$

General Formulas and Concepts:

Algebra I

Factoring

Calculus

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C$

Step-by-step explanation:

Step 1: Define

$\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx$

Step 2: Integrate Pt. 1

[Integral] Factor fraction denominator: $\displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx$
[Integral] Integration Property - Multiplied Constant: $\displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx$

Step 3: Identify Variables

Set up u-substitution for the arctan trig integration.

$\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx$

Step 4: Integrate Pt. 2

[Integral] Substitute u-du: $\displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C$
[Integral] Simplify: $\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C$
[integral] Multiply: $\displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C$
[Integral] Back-Substitute: $\displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C$

Topic: AP Calculus AB

Unit: Integrals - Arctrig

Book: College Calculus 10e

7 0

2 years ago

Factor each trinomial. Then match the polynomial (term) on the left with its factored form (definition) on the right.

meriva

X² - 8x - 20 factors to give option
B) (x - 10)(x + 2)
x² + 8x - 20 factors to give option
A) (x - 2)(x + 10)
x² - x - 20 factors to give option C) (x - 5)(x + 4)
and x² - 9x - 20 is option D) Prime.

I hope this helps!

8 0

2 years ago

Read 2 more answers

Using a simulator at space camp, you practice landing your individual spaceship on landing platforms that have different shapes

Mila [183]

The Area of the platform is 33m²

Step-by-step explanation:

As the question says, the height of vertex from the base (D from AB) is 7m whereas the height of left vertex from the base (E from AB) is 4m

Thus it means the height of the Δ DCE (DX)= 7-4 ⇒3m

Since the platform is five-sided, the figure can be broken down into constituting parts

Parallelogram ║ABCE
Δ DCE

Are of the figure= Area of ║ABCE+ area Δ DCE

Area of ║ABCE= breadth * height

= 6*4 ⇒24m ²

Area Δ DCE= ½*(base)(height)

Putting the value of base is 6m and height as 3m

Area Δ DCE= ½*6*3

=9m ²

Total area= 24+9= 33m ²

3 0

2 years ago

Please help me IDK how to do this!!!!!!

tatiyna

A parallelogram should have 2 sets of parallel lines. Let's find the slope of line PQ and RS to test.

PQ:
(4-2)/(1-(-3))
2/4
1/2

RS:
(2-0)/(3-1)
2/2
1

Because 1 does not equal 1/2 (the slopes are different) the lines are not parallel. Thus, the figure is not a parallelogram.

5 0

2 years ago