Answer:
√2=1.414
then :√8 +2√32 +3√128+4√50
√8=√2³ =2√2
2√32=√2^5 = 4*2√2 = 8√2
3√128 = 3√2^6*2=8*3√2 =24√2
4√50 =4√5²*2= 20√2
add results : 2√2+8√2 +24√2+20√2=54√2
<h2>
54√2=54×1.414=76.356 ( it is not in the options)</h2>
x=7-4√3
√x+ 1/√x
√(7-4√3) +1/√(7-4√3) =
(8-4√3)/√(7-4√3)
(8-6.93)/√(7-6.93) = 4 ( after rounded to the nearest whole number)
4 is your answer
I believe it’s b I am not sure
Step by step explanation
Answer:
m = 10 / 5 = 2 / 1 = 2
Step-by-step explanation:
I think that it would be true, but, don't make me promise that it's right, lol XD
Answer:
1/7 (option d) of the sensors on the satellite have been upgraded
Step-by-step explanation:
Each unit contains the same number of non-upgraded sensors
number of non-upgraded sensors for each module (nus)
total number of upgraded sensors on the satellite (tus)
satellite is composed of 30 modular units
total number of non-upgraded sensors on the satellite (tnus):
tnus=30*nus
total number of sensors on the satellite (ts):
ts=tnus+tus = 30*nus + tus (I)
The number of non-upgraded sensors on one unit is 1/5 the total number of upgraded sensors on the entire satellite
nus=(1/5)*tus
tus = 5 * nus (II)
Fraction of the sensors on the satellite have been upgraded (FU):
FU = tus/ts
Using I and II
FU= (5* nus)/(30*nus + tus)
FU = (5* nus)/(30*nus + 5 * nus)
FU = (5* nus)/(35*nus)
FU = 1/7
1/7 (option d) of the sensors on the satellite have been upgraded
