Answer:
3u(u - 2)
Step-by-step explanation:
greatest common factor: 3u (both are divisible by 3, and include the variable u)
factor: 3u^2/3u = u; -6u/3u = 2
new polynomial: 3u(u - 2)
Answer:
X=6 and Y=3
Step-by-step explanation:
Use SOHCAHTOA, SOH, Sin=Opposite/Hypotenuse, Therefore Sin60°=(3√3)/x ; Xsin60°=3√3 and Sin60° without using 4figuretable or calculator is √3/2, Now x=3√3 ÷√3/2 ;. therefore X=3√3×2/√3= 6. X=6 . Using Pythagoras theorem, 6²={(3√3)² +y²}. Y²= 36-27=9. Y=√9, Y=3. Therefore X=6 and Y=3.
Answer: (0,0),(0,4), and (5,0)
Step-by-step explanation:
It is easy to find lengths of horizontal and vertical segments and distances from (0,0) so always place one vertex at the origin and one or more sides on an axis.
This answer has an x intercept and y intercept.
Answer:
The probability that there are 3 or less errors in 100 pages is 0.648.
Step-by-step explanation:
In the information supplied in the question it is mentioned that the errors in a textbook follow a Poisson distribution.
For the given Poisson distribution the mean is p = 0.03 errors per page.
We have to find the probability that there are three or less errors in n = 100 pages.
Let us denote the number of errors in the book by the variable x.
Since there are on an average 0.03 errors per page we can say that
the expected value is,
= E(x)
= n × p
= 100 × 0.03
= 3
Therefore the we find the probability that there are 3 or less errors on the page as
P( X ≤ 3) = P(X = 0) + P(X = 1) + P(X=2) + P(X=3)
Using the formula for Poisson distribution for P(x = X ) = 
Therefore P( X ≤ 3) = 
= 0.05 + 0.15 + 0.224 + 0.224
= 0.648
The probability that there are 3 or less errors in 100 pages is 0.648.
Answer:
I am pretty sure the answer is A
Step-by-step explanation: