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2 years ago

Which solution for the value of x in the figure below is incorrect? explain

Mathematics

1 answer:

ruslelena [56]2 years ago

4 0

B is wrong because they are not supplementary. they a alternate interior angels so they are equal

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Pls help oooooooooooooopoo

grigory [225]

9514 1404 393

Answer:

140°

Step-by-step explanation:

Angles 1 and 3 are "corresponding" angles, so are congruent.

∠1 = ∠3

20x +60 = 30x +20

40 = 10x . . . . . . . . . . . . subtract 20x+20

4 = x . . . . . . . . . . . . . . divide by 10

∠1 = 20x +60 = 20(4) +60 = 80 +60

∠1 = 140°

3 0

2 years ago

Read 2 more answers

I don’t know the answer

anastassius [24]

I THINK IT IS B

B) D(X)= X-8x4

7 0

2 years ago

What's the ratio of 75 to 80?

oksano4ka [1.4K]

Answer:

75:80 OR 15:16

Step-by-step explanation:

7 0

2 years ago

One root of a third degree polynomial function f(x) is –5 + 2i. Which statement describes the number and nature of all roots for

Marat540 [252]

Answer:

Step-by-step explanation:

f(x) has two complex roots and one real root.

8 0

2 years ago

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Evaluate the cosine if the angle of rotation which contains the point (9, -3) on its terminal side

Liono4ka [1.6K]

so we know the terminal point is at (9, -3), now, let's notice that's the IV Quadrant

$\bf (\stackrel{x}{9}~~,~~\stackrel{y}{-3})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{9^2+(-3)^2}\implies c=\sqrt{81+9}\implies c=\sqrt{90} \\\\[-0.35em] ~\dotfill$

$\bf cos(\theta )=\cfrac{\stackrel{adjacent}{9}}{\stackrel{hypotenuse}{\sqrt{90}}}\implies \stackrel{\textit{rationalizing the denominator}}{\cfrac{9}{\sqrt{90}}\cdot \cfrac{\sqrt{90}}{\sqrt{90}}\implies \cfrac{9\sqrt{90}}{90}}\implies \cfrac{\sqrt{90}}{10}\implies \cfrac{3\sqrt{10}}{10}$

6 0

2 years ago