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kodGreya [7K]
3 years ago
11

0.34156020 as a scientific notation

Mathematics
2 answers:
Svetach [21]3 years ago
8 0

Answer:

= 3.4156020 × 10-1

Step-by-step explanation:

Ilia_Sergeevich [38]3 years ago
5 0

Answer:

3.4156020*10^-1 for scientific notation if you want to keep that ending zero (I'd normally write it 3.415602*10^-1)

Step-by-step explanation:

So the idea of scientific notation (or engineering notation) is to make things smaller and more manageable. The idea is to move the variables so that one is in front of the point.

So if you had something like this:

12342300000000000000

It'd be equal to 1.23423*10^19

Or something like this

0.0000095675

Would be 9.5675*10^-6

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Alondra is grocery shopping for her mother. She has $12 to spend. She must buy one gallon of milk and some boxes of cereal. The
Kaylis [27]
She can buy 4 boxes of cereal
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7 0
4 years ago
Read 2 more answers
What is the surface area of the rectangular pyramid below? B = 4.8 m
GuDViN [60]

Answer:

625 unit²

Step-by-step explanation:

Surface area of a rectangular pyramid :

Area of base * 4(area of triangular side)

Area of base = length * width

Area of base = 15 * 15 = 225

Height of triangular side = 15

Area of triangle = 1/2 * base * height

Area of triangle = 1/2 *15 * 15 = 112.5 unit²

Surface area = 225 + 4(112.5)

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4 0
3 years ago
The probability of the spinner landing on the shaded part is p=1/3. The probability of it landing on an unshaded part is q=2/3 t
raketka [301]

Answer:

The correct answer is 0.5.

Step-by-step explanation:

The probability of a spinner landing on the shaded part follows binomial distribution.

Equation to be used is P(r) = \left[\begin{array}{ccc}n\\r\end{array}\right]  × p^{r} × q^{n-r} , where n is the number of times the spinner is spun and r is the number of times the spinner falls on the shaded region.

The probability of the spinner landing on the shaded part is p = \frac{1}{3}. The probability of it landing on the unshaded part is q = \frac{2}{3}.

The spinner is spun n = 3 times.

We need to find the probability of it landing on the shaded part r = 2.

∴ Putting the values in the equation gives,

P(r) = \left[\begin{array}{ccc}3\\2\end{array}\right]  × \frac{1}{2} ^{2} × \frac{2}{3} ^{1} = 3 × \frac{2}{3} × \frac{1}{4} = 0.5

8 0
3 years ago
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