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Marina86 [1]
2 years ago
6

Rewrite 3^-4 without negative exponents a. 81 b. -81 c. 1/81 d. -1/81

Mathematics
1 answer:
vodka [1.7K]2 years ago
7 0
<h3>Answer</h3>

1/81(C)

<h3>Step-by-step solution</h3>

(3)^4=81

if 3^-1=1/3

so, 3^-4=1/81(C)

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Which of the following can be a Pythagorean triplets?:
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<h2>Answer :-</h2>

As we know that,

Pythagoras triplet

1) a² + b² = c²

Let

\sf \: {2}^{2} + {2}^{2} = {4}^{2}

\sf \: 4 + 4 = 16

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<h3>Hence, A can't be Pythagoras triplet</h3>

2) a² + b² = c²

\sf \:5 {}^{2} + {12}^{2} = {13}^{2}

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<h3>Therefore, B can be Pythagoras triplet</h3>

3)a² + b² = c²

\sf {3}^{2} + {5}^{2} = {6}^{2}

\sf 9 + 25 = 36

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<h3>Hence, C can't be Pythagoras triplet</h3>

4) a² + b² = c²

\sf {5}^{2} + {4}^{2} = {7}^{2}

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<h3>Hence, D can't be Pythagoras triplet</h3>

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Only B can be Pythagoras triplet.

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