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3 years ago

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On Sunday, a local hamburger shop sold a combined total of 536 hamburgers and cheeseburgers. The number of cheeseburgers solid w

as three times the
number of hamburgers sold. How many hamburgers were sold on Sunday?
Il hamburgers

1 answer:

aleksklad [387]3 years ago

3 0

Answer:

134 hamburgers sold on Sunday

Step-by-step explanation:

x+3x=536

4x=536

4x/4=x, 536/4=134

x=134

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A 12-meter ladder leans against a building forming a 30° angle with the building.

KatRina [158]

Answer:

will show you two (2) ways to solve this problem.

A diagram is needed to see what is going on....

Without loss of generality (WLOG)

The wall is on the right. The ladder leans against the wall

with a POSITIVE slope, from SW to NE (quadrant 3 to quadrant 1).

The measure from the bottom of the ladder to the wall is 6.

Option 1:

The ladder, ground and wall form a right triangle.

The hypotenuse (ladder) is 14 feet.

The bottom of the ladder is 6 feet from the wall,

so the base of this right triangle is 6 feet.

The top of the ladder to the ground represents

the missing leg of the right triangle.

The pythagorean theorem applies, which says

6^2 + h^2 = 14^2 where h is the height

of the top of the ladder to the ground

36 + h^2 = 196

h^2 = 196 - 36

h^2 = 160

h = sqrt(160)

= sqrt(16 * 10)

= sqrt(16)* sqrt(10)

= 4*sqrt(10) <--- exact answer

= 4 * 3.16227766016838....

= 12.64911....

12.65 <--- rounded to 2 digits as directed

----------------------------------------------

Option #2: using trig

With respect to the angle formed by the bottom of the

ladder with the ground

cos T = 6/14 = 3/7

T = inverse-cosine(3/7) = 64.623006647 degrees

sin(64.623006647) = h/14

h = 14*sin(64.62300647) = 12.6491106 <--- same answer

hope this helps

Step-by-step explanation:

5 0

3 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

<u>━━━━━━━━━━━━━━━━━━━━</u>

5 0

3 years ago

Read 2 more answers

For the following geometric sequence find the recursive formula: {-1, 3, -9, ...}.

vredina [299]

First term (a1) is -1

recursive formula goes like this

$a_n$ is the nth term
$a_{n-1}$ is the term before that

we normally have $a_n=f(a_{n-1})$

we see each term is multipying by -3 to get next one

so that would be
$a_n=-3*a_{n-1}$ where a1=-1

the 3rd option is correct except that it is the explicit formula

so answer is 2nd one

3 0

3 years ago