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labwork [276]
3 years ago
7

Ervin sells vintage cars. Every three months, he manages to sell 13 cars. Assuming he sells cars at a constant rate, what is the

slope of the line that represents this relationship if time in months is along the x-axis and the number of cars sold is along the y-axis?
Mathematics
2 answers:
raketka [301]3 years ago
4 0

Answer:  4.33\text{ cars per month.}

Step-by-step explanation:

Given : Ervin sells vintage cars. Every three months, he manages to sell 13 cars.

m=\dfrac{\text{change in y}}{\text{change in x}}

If time in months is along the x-axis and the number of cars sold is along the y-axis

Change in months : 3

Change number of cars : 13

The slope of the line that represents this relationship will be :-

m=\dfrac{\text{Change in cars}}{\text{Change in months}}\\\\=\dfrac{13}{3}=4.33333\approx4.33\text{ cars per month.}

Hence, the slope of the line = 4.33\text{ cars per month.}

Minchanka [31]3 years ago
3 0
The slope would be 4.33. He sells 13 cars in 3 months, 13/3=4.33 cars each month. While you can't sell 4.33, remember that this is just the slope. The equation would be apprx y=4.33(x)
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barxatty [35]

Answer:

Part A: The average car length is 9.1 feet to the nearest tenth foot

Part B: The line would be 9100 feet to contained 1000 cars

Step-by-step explanation:

* Lets explain how to solve the problem

# Part A:

- There were 62 cars in a line that stretched 567 feet

- The cars are lined up bumper-to-bumper

- That means there is no empty spaces between the cars

* To find the average length of the car we will divide the length of

  the line by the numbers of the cars

∵ The average car length = length of the line/number of cars

∵ The length of the line is 567 feet

∵ The numbers of the cars is 62 cars

∴ The average car length = 567/62 = 9.1 feet

* The average car length is 9.1 feet to the nearest tenth foot

# Part B:

- There are 1000 cars

- We need to find the length of line which contained the cars

∵ The average car length = length of the line/number of cars

∵ The average of car length is 9.1 feet

∵ The number of the cars is 1000 cars

∴ 9.1 = length of the line/1000

- Multiply both sides by 1000

∴ The length of the line = 9.1 × 1000 = 9100 feet

∴ The line would be 9100 feet to contained 1000 cars

7 0
3 years ago
Evaluate and answer in standard form:<br><br>4^2/3^2​
Semenov [28]

the answer is : 1.7777

6 0
3 years ago
Here are 7 numbers.
SIZIF [17.4K]

Answer:

3.06

I hope this helps you :)

4 0
2 years ago
Solve for x. −23(3x−4)+3x=56
labwork [276]

Answer:

x = 6/11

Step-by-step explanation:

−23(3x−4)+3x=56

Distribute

-69x + 92 +3x = 56

Combine like terms

-66x+92 = 56

Subtract 92 from each side

-66x+92-92 = 56-92

-66x =-36

Divide each side by -66

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7 0
2 years ago
Convert 0.063 to scientific notation
Firdavs [7]
The answer = 6.3 × 10-2
(scientific notation)

= 6.3e-2
(scientific e notation)

= 63 × 10-3
(engineering notation)
(thousandth; prefix milli- (m))

= 0.063
<span>(real number)</span>
5 0
3 years ago
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