Answer: it is linear because no bumps.
Step-by-step explanation:
Answer:
its the top right
Step-by-step explanation:
x before y
Y = xe^x
dy/dx(e^x x)=>use the product rule, d/dx(u v) = v*(du)/(dx)+u*(dv)/(dx), where u = e^x and v = x:
= e^x (d/dx(x))+x (d/dx(e^x))
y' = e^x x+ e^x
y'(0) = 1 => slope of the tangent
slope of the normal = -1
y - 0 = -1(x - 0)
y = -x => normal at origin
<u>Hint </u><u>:</u><u>-</u>
- To find out the equation of the line we can use the point slope form of the line which is
<u>Solution</u><u> </u><u>:</u><u>-</u>
The given point to us is ,
and the slope of the line is 4 . On using the point slope form , we have ,
<u>Hence</u><u> the</u><u> </u><u>equation</u><u> </u><u>is </u><u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>y </u><u>+</u><u> </u><u>3</u><u> </u><u>=</u><u> </u><u>0</u><u> </u>
( for graph , see attachment ) .
The domain is {the smallest x value with a point, the largest x value with a point} on the graph