All categories

3 years ago

An electron is in a region outside the nucleus. An electron ____________.

Chemistry

2 answers:

shusha [124]3 years ago

6 0

Answer:

An electron is in a region outside the nucleus, has less mass than a proton and has a negative charge.

Explanation:

Electrons are considered as a negatively charged particle, as they are surrounded by the kind of invisible force called the electrostatic force.

HOPE IT HELPS

motikmotik3 years ago

6 0

An electron that’s in a region outside the nucleus is called an orbital

You might be interested in

In examining an organic compound, you discover that it contains the following functional group. What class of organic compound i

Romashka [77]

Option B. carboxylic acid

For example

CH3 - COOH, is the acetic acid or etanoic acid.

where - COOH is C bonded with O (trhough doble bond) and with OH (with a single bond)

8 0

3 years ago

How many moles are in 7950 g of CO2? ( pleas show calculation)

Mkey [24]

Answer:

Calculate the number of moles of CO2 by the formula n=PV/RT, where P is the pressure from Step 3, V is the volume from Step 2, T is the temperature from Step 1 and R is a proportionality constant equal to 0.0821 L atm / K mol.

Explanation:

6 0

3 years ago

The volume of a sample of oxygen is 300mL when the pressure is 1 atm and the temperature is 27 C . At what temperature is the vo

LenaWriter [7]

Answer:

T2 = 500K

Explanation:

Given data:

P1 = 1atm

V1 = 300ml

T1= 27 + 273 = 300K

T2 = ?

V2 = 1.00ml

P2 = 500atm

Apply combined law:

P1xV1//T1 = P2xV2/T2 ...eq1

Substituting values into eq1:

1 x 300/300 = 500 x 1/T2

Solve for T2:

300T2 = 500 x 300

300T2 = 150000

Divide both sides by the coefficient of T2:

300T2/300 = 150000/300

T2 = 500K

8 0

4 years ago

The variables for this experiment include the height of the track and the speed of the car. Use the drop-down menus to complete

nekit [7.7K]

Answer:

we dont know the options

Explanation:

3 0

3 years ago

A certain liquid X has a normal boiling point of 118.90 °C and a boiling point elevation constant Kb = 0.82 °C*kg*mol^-1. Calcul

Fantom [35]

Answer: The boiling point of solution is $1.2\times 10^2^oC$

Explanation:

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

Or,

$\Delta T_b=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

where,

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}$

Boiling point of pure liquid = 118.90°C

i = Vant hoff factor = 2 (For potassium bromide)

$K_b$ = molal boiling point elevation constant = 0.82°C/m

$m_{solute}$ = Given mass of solute (potassium bromide) = 54. g

$M_{solute}$ = Molar mass of solute (potassium bromide) = 119 g/mol

$W_{solvent}$ = Mass of solvent (liquid X) = 750. g

Putting values in above equation, we get:

$\text{Boiling point of solution}-118.90=2\times 0.82^oC/m\times \frac{54\times 1000}{119g/mol\times 750}\\\\\text{Boiling point of solution}=119.9^oC=1.2\times 10^2^oC$

Hence, the boiling point of solution is $1.2\times 10^2^oC$

7 0

4 years ago

An electron is in a region outside the nucleus. An electron ____________.​

An electron is in a region outside the nucleus. An electron ____________.