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2 years ago

NEEEED help with 2 and 4?!

Mathematics

1 answer:

muminat2 years ago

8 0

Answer:

ex 2

is d 66 and ex 4 don't know

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5.7 as an improper fraction

harkovskaia [24]

Answer:

5.7 = $\frac{57}{10}$ as an improper fraction

Step-by-step explanation:

When dividing a number by 10 the decimal moves one place to the left. When we take 57 and divide it by 10, we get 5.7

5 0

2 years ago

Please help. Thank you

love history [14]

Answer:

The length of side x is $x = \sqrt{6}$

Step-by-step explanation:

Pythagorean Theorem:

In a right triangle, with sides a and b, and hypothenuse h, we have that:

$a^2 + b^2 = h^2$

In this question:

The vertical line on the sides means that both are equal, that is, measuring x, so $a = b = x$ .

Hypothenuse is the square root of 12. So $h = \sqrt{12}$

$x^2 + x^2 = (\sqrt{12})^2$

$2x^2 = 12$

$x^2 = \frac{12}{2}$

$x^2 = 6$

$x = \sqrt{6}$

The length of side x is $x = \sqrt{6}$

8 0

2 years ago

What is 2 and 6/7 times 4/5

bulgar [2K]

Answer:

Step-by-step explanation:

2 6/7 * 4/5....turn ur mixed number into an improper fraction and just multiply

20 / 7 * 4 / 5 = 80/35 which reduces to 16/7 or 2 2/7

4 0

2 years ago

What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

2 years ago

the width of a rectangle is 2 inches less than it's length,and the area is 35 square inches.What are the length and width of the

Sergeu [11.5K]

7 for the length and 5 for the width. 7 x 5 = 35

6 0

2 years ago

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