Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
<h3>
Answer is the ratio 1000:193:61</h3>
Explanation
1 liter = 1000 mL
For every 1000 mL of water, we need 193 mL of sucrose and 61 mL of saline solution.
The ratio is therefore 1000:193:61
We cannot simplify this ratio any further because the GCF of those three terms is 1.
A quick way to see this is to look at how 1000 = (2*5)^3 has prime factors 2 and 5, but 2 nor 5 are factors of 193 and 61. So only 1 is a factor of all three values 1000, 193, 61
Answer:
6:10.
Step-by-step explanation:
4 : 40 + 1 : 30 = 5 : 70
because 60 minutes make an hour and on the minutes side has more than 60, we have to minus 60 minutes and carry the one hour to the other side which is the Hour side.
5 : 70........ minus 60 to get 10.
5 + 1 to get 6.
therfore it is 6 : 10
Answer:
x=25°
Step-by-step explanation:
The given angle is a 90° angle. We know this because of the little square in the corner. This means that both angles must add up to 90°:
Insert the known values:
Solve for x. Subtract 65 from both sides:
The missing angle, x°, is 25°.
:Done
