NEEEED help with 2 and 4?!

If r= 9 units and x = 4 units, then what is the volume of the cylinder shown above?

Thepotemich [5.8K]

Answer:

Volume of the cylinder is. 1017.36

Step-by-step explanation:

$V=\pi r^2h$ is the area of a cylinder.

Let's plug in our values.

-----

3.14 = pi

9 = radius

x = height

-----

V = (3.14)(9)^2(4)

V = (3.14)(81)(4)

V = (3.14)(324)

V = 1017.36

3 0

3 years ago

Both questions//Congruence

Gemiola [76]

Answer:

first one: 53°

Second one: reflective property of congruence <-(I'm not sure on this one but it seems like it)

Step-by-step explanation:

First one:

The measure of every triangle is 180°

we have to find that missing angle

so 180-53-74=53°

If its harder to understand you can make angle E x and solve 180=x+53+74

For the second one:

The reflexive property of congruence states that any geometric figure is congruent to itself.

This means that even same line segments and be congruent because of this property.

I hope this helped

8 0

3 years ago

Sylvie finds the solution to the system of equations by graphing.

Softa [21]

Answer:

The correct answer is:

A coordinate grid with 2 lines. The first line passes through the points (negative 1.5, 0), (0, negative 1), and (3, negative 3). The second line passes through the points (negative 1.5, 0), (0, 1), and (3, 3).

Step-by-step explanation:

We are given the system of equations as:

$1.\ y=-\dfrac{2}{3}x-1\\2.\ y=\dfrac{2}{3}x+1\\$

We have 2 equations here with variables x and y so we use coordinate grid with 2 lines having axis as x and y.

As per the given options, we can see that coordinate of one point has y = 0 and other point has x = 0.

So, let us put y = 0 and x =0, in both the equations one by one and have a look at the value of x coordinate.

y = 0, Equation (1) becomes:

$0=-\dfrac{2}{3}x-1\\\Rightarrow 1 =-\dfrac{2}{3}x\\\Rightarrow x = - 1.5$

So, one coordinate is (-1.5, 0)

x = 0, Equation (1) becomes:

$y=-\dfrac{2}{3}\times 0-1\\\Rightarrow y =-1$

So, other coordinate is (0, -1)

And the point (3, -3) also satisfies the given equation.

y = 0, Equation (2) becomes:

$0=\dfrac{2}{3}x+1\\\Rightarrow 1 =-\dfrac{2}{3}x\\\Rightarrow x = - 1.5$

So, one coordinate is (-1.5, 0)

x = 0, Equation (2) becomes:

$y=\dfrac{2}{3}\times 0+1\\\Rightarrow y =1$

So, other coordinate is (0, 1)

And the point (3, 3) also satisfies the given equation.

Please refer to the attached graph and points on lines.

So, correct answer is:

A coordinate grid with 2 lines. The first line passes through the points (negative 1.5, 0), (0, negative 1), and (3, negative 3). The second line passes through the points (negative 1.5, 0), (0, 1), and (3, 3).