Answer:
Step-by-step explanation:
Solution by substitution method
3x+5y=7
and 4x-y=5
Suppose,
3x+5y=7→(1)
and 4x-y=5→(2)
Taking equation (2), we have
4x-y=5
⇒y=4x-5→(3)
Putting y=4x-5 in equation (1), we get
3x+5y=7
⇒3x+5(4x-5)=7
⇒3x+20x-25=7
⇒23x-25=7
⇒23x=7+25
⇒23x=32
⇒x=32/23
→(4)
Now, Putting x=32/23
in equation (3), we get
y=4x-5
⇒y=4(32/23)-5
⇒y=(128-115)/23
⇒y=13/23
∴y=13/23 and x=32/23
Answer:
-3 ≤y≤6
Step-by-step explanation:
The range is the output values or the y values
The y values go from -3 to 6 including these values
-3 ≤y≤6
Answer:
KL = 16
Step-by-step explanation:
For this problem, JL is the sum of KL and JK. So we can say this:
JK + KL = JL
( 3x + 6 ) + ( 5x + 6 ) = 28
8x + 12 = 28
8x = 16
x = 2
So, now we can find KL:
5x + 6 = ?
5(2) + 6 = ?
10 + 6 = ?
16 = ?
So the length of KL is 16.
Cheers.
Answer:
44
Step-by-step explanation:
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