Given: The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula $P=a^{\frac{3}{2}$ .

Saturn’s orbital period P = 29.5 years

Substitute this value in the equation above, we get

$29.5=a^{\frac{3}{2}}\\\Rightarrow(29.5)^{\frac{2}{3}}=a\\\Rightarrow\ a=9.54731702\text{ astronomical units}$

Hence, its distance from the sun = 9.54731702 astronomical units.

3 0

3 years ago

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Write short note on the rule on how to bisect a perpendicular angle

coldgirl [10]

Answer:

Given a line segment AB

open the compass more than half of the distance between A and B, and scribe arcs of the same radius centered at A and B.

Call the two points where these two arcs meet C and D. Draw the line between C and D.

CD is the perpendicular bisector of the line segment AB. Call the point where CD intersects AB E.

Step-by-step explanation:

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8 0

3 years ago

Evaluate the expression when x = 1/4 and y = 8 2(10-24x) + y^2

Whitepunk [10]

The answer is 72,
Work-
2(10-24•1/4)+8^2
2(10-6)+64
2(4)+64
8+64=72

4 0

4 years ago