Question

HELP! Please show full solutions. Will mark brainliest for THE BEST ANSWER. THANK YOU.

Answer 1

Answer:

Step-by-step explanation:

$4)a) Time =\dfrac{Distance}{Speed}$

Micky:

Distance covered = 30 Km   {Leg A}

Speed = x Kmph

Minnie:

Distance covered = 20 Km  {Leg B}

Speed = y Kmph

$Total \ time = \dfrac{30}{x}+\dfrac{20}{y}$

b) x = 35 Km/h

y = 25 Km/h

$Total \ time = \dfrac{30}{35}+\dfrac{20}{25}\\\\ = \dfrac{6}{7}+\dfrac{4}{5}\\\\=\dfrac{6*5}{7*5}+\dfrac{4*7}{5*7}\\\\=\dfrac{30+28}{35}\\\\=\dfrac{58}{35}\\\\=1\dfrac{23}{35} \ hours$

Answer 2

Answer:

See Below

Step-by-step explanation:

A)

There are two runners that run at different average speeds, let these be Ra (runner a) and Rb (runner b). We also have two differnt distances that can be ran, let Leg A La and Leg b Lb. We get the equation bellow:

$Total time = L_a/R_1 + L_b/R_2$

B)

Mickey = 35km/h

Minnie = 25km/h

Leg A = 30

Leg B = 20

Since Mickey is the fastes, he should run the section with the longest distance:

$Total time = L_a/R_1 + L_b/R_2\\Total time = 30_k_m/35_k_m_/_h + 20_k_m/25_k_m_/_h\\Total time = (30/35)_h + (28/35)_h\\Total time = (58/35)_h$