For the first one:tick the second to last.
for the second: tick the first circle.
for the third: tick the second to last.
for the forth: tick the second.
for the fifth: tick the last.
for the last one: tick the second.
Hope it helps...
By definition of conditional probability,
P(B | A) = P(A ∩ B)/P(A) = (13/25) / (13/20) = 20/25 = 4/5
Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
34x=0
So we need to isolate x. Since 34 is multiplied by x, we need to isolate x by moving 34 over the equal sign. Whenever you move something over the equal sign, the opposite is done. For 34, instead of being multiplied, it will be divided.
34x=0
X=0/34
Then you solve for x
X=0
Hope this helps!
