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Contact [7]
3 years ago
8

Factor : 49c^2 - 25d^6

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0
49c^2 - 25d^6
(7c)^2 - (5d^3)^2
(7c + 5d^3)(7c - 5d^3)

The answer is: (7c + 5d^3)(7c - 5d^3).
vichka [17]3 years ago
7 0
Hello,

49c^{2}-25d^{6}=(7c)^2-(5d^3)²=[7c-5d^3][7c+5d^3]

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If an arithmetic sequence has a 10th term of 17 and a 14th term of 30. find the common difference (d).
stellarik [79]

Answer:

common difference is 13/4

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1 year ago
Write the Roman Numeral CLXIV in standard form. Roman Numeral Standard Number 1 5 10 50 100 500 1,000 X L C D A) 169 B) 166 C) 1
elena-14-01-66 [18.8K]

Answer:

164

Step-by-step explanation:

in standard form CLXIV IS 164

5 0
2 years ago
a polygon has the same number of angles as it it has to be in a regular polygon all the sides congruent and all angles are congr
QveST [7]
A regular polygon is a polygon that has angles with all the same degree and the side length of the line segments the polygon is made of has all the same length.
5 0
3 years ago
Find the distance between the pair of parallel lines with the given equations.
ZanzabumX [31]

The distance between the two parallel lines is 26 units

<h3>What is are parallel lines?</h3>

Parallel lines are lines that do not meet or intersect.

If y = mx +c as the equation of a straight line

For the line y = -5x

comparing with the standard equation of a line,

y = -5x has no y-intercept, so the coordinates of the point is (0,0)

For the second line y = -5x + 26

comparing with the standard equation

The y-intercept is 26, which means the coordinates of the point is (0, 26)

The distance between these two points is the distance between the two lines.

Formula for distance between two point,

D = \sqrt{(y_{2} -y_{1}) ^{2} + (x_{2} - x_{1}) ^{2}  }

D = \sqrt{(26-0)^{2} + (0-0)^{2} }

D = 26 units

In conclusion, the distance between the two parallel lines is 26 units

Learn more about parallel lines: brainly.com/question/24607467

#SPJ1

8 0
1 year ago
The Candy Factory sells candy by the pound, charging $1.60 per pound for quantities up to and including 20 pounds. Above 20 poun
rusak2 [61]

Answer:

k=6

Step-by-step explanation:

We have been given that the Candy Factory sells candy by the pound, charging $1.60 per pound for quantities up to and including 20 pounds. Above 20 pounds, the Candy Factory charges $1.30 per pound for the entire quantity, plus a quantity surcharge k.

\left \{ {{p(x)=1.6x, \text{ If }x\leq 20} \atop {p(x)=1.30x+x,\text{ if }x>20}} \right.

For the price function be to continuous at x=20, the value of both functions at x=20 must be equal. Because a function is continuous if the right hand limit is equal to left hand limit.

1.6(20)=1.3(20)+k

Let us solve for k.

32=26+k

32-26=26-26+k\\\\6=k

Therefore, the price function p is continuous at  x=20, when k is equal to 6.

5 0
3 years ago
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