Marco walked while his sister Amy ran at the track. Their distances and times are shown on the graph

If pentagon OPQRS is dilated by a scale factor of seven over four from the origin to create O'P'Q'R'S', what is the ordered pair

GrogVix [38]

Answer:

The order pair of point Q' is (-21/4 , -7/2)

Step-by-step explanation:

* Lets explain the dilation

- A dilation is a transformation that changes the size of a figure.

- The figure can become larger or smaller, but the shape of the

figure does not change.

- The scale factor, measures how much the image will be larger

or smaller

- If the scale factor greater than 1, then the image will be larger

- If the scale factor between 0 and 1, then the image will be smaller

- The center of dilation is a fixed point in the plane about which all

points are expanded or contracted

* Lets solve the problem

- The pentagon OPQRS is dilated by a scale factor 7/4

- The center of dilation is the origin

- The image of the pentagon after the dilation is O'P'Q'R'S'

∵ The coordinates of the vertices of the pentagon OPQRS are

O (-1 , 2) , P (-5 , 3) , Q (-3 , -2) , R (2 , 1) , S (2 , 5)

- To find the image of each point after the dilation multiply each

coordinates of the points by the scale factor of dilation

∵ The scale factor is 7/4

∵ The coordinates of point Q are (-3 , -2)

∴ The image of point Q after dilation is (-3 × 7/4 , -2 × 7/4)

∴ The image of point Q after dilation is (-21/4 , -7/2)

∵ Q' is the image of Q

∴ Q' = (-21/4 , -7/2)

* The order pair of point Q' is (-21/4 , -7/2)

5 0

4 years ago

Read 2 more answers

42/-8 Divide<br><br> Please answer asap

krok68 [10]

It's -5.25 because 5*8 is 40 and 6*8 is 48.

5 0

3 years ago

Read 2 more answers

Number 13 please show me in the least steps possible

spayn [35]

$\frac{\sqrt3}{-\sqrt{21}}=-\sqrt\frac{3}{21}=-\sqrt\frac{1}{7}=-\frac{\sqrt1}{\sqrt7}=-\frac{1}{\sqrt7}=-\frac{1}{\sqrt7}\times\frac{\sqrt7}{\sqrt7}=-\frac{\sqrt7}{7}$

3 0

4 years ago

Read 2 more answers

PLEASE HELP!!!!!!!<br>please

Nataly_w [17]

Answer:

see explanation

Step-by-step explanation:

To find the zeros let h(t) = 0, that is

t² + 4t + 3 = 0 ← in standard form

(t + 3)(t + 1) = 0 ← in factored form

Equate each factor to zero and solve for t

t + 3 = 0 ⇒ t = - 3 ← smaller t

t + 1 = 0 ⇒ t = - 1 ← larger t

(2)

given a parabola in standard form : ax² + bx + c ( a ≠ 0)

Then the x- coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$

h(t) = t² + 4t + 3 ← is in standard form

with a = 1 and b = 4, thus

$x_{vertex}$ = - $\frac{4}{2}$ = - 2

Substitute t = - 2 into h(t) for y- coordinate

h(- 2) = (- 2)² + 4(- 2) + 3 = 4 - 8 + 3 = - 1

Vertex = (- 2, - 1 )

4 0

3 years ago

For the order of operations, Group of answer choices Multiplication, division and remainder is performed first Addition and subt

Furkat [3]

Answer: Addition and subtraction is performed after multiplication, division and remainder

Step-by-step explanation:

The correct order of operations is to calculate whatever is in the parenthesis first.

Then calculate multiplication and division depending on which comes first as you move from left to right.

Then addition and subtraction can be performed also depending on which comes first as you move left to right.

8 0

3 years ago