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erastovalidia [21]
3 years ago
8

Plas answer my clipped question

="plsss \: lang \: po" alt="plsss \: lang \: po" align="absmiddle" class="latex-formula">
​

Mathematics
2 answers:
katen-ka-za [31]3 years ago
8 0
<h3><u>Required Answers :</u></h3>

8) Option D

  • The opposite of -20 is equal to the opposite value of -20 which means 20 as -20 is opposite of 20

9) Option D (150)

10) Option B ( -3, -2, 0, 4, 5, 9, 10)

11) Option C |20|

12) Option B ( -1, 0, 1, 2)

13) Option D (18)

14) Option D (5)

15) Option D (10)

Lapatulllka [165]3 years ago
5 0
8 - D
9 - D
10 - B
11 - C
12 - B
13 - D
14 - D
15 - D
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Valentin [98]

It looks like the integral is

\displaystyle \iint_D x^2 (y-x) \,\mathrm dx\,\mathrm dy

where <em>D</em> is the set

<em>D</em> = {(<em>x</em>, <em>y</em>) : 0 ≤ <em>x</em> ≤ 1 and <em>x</em> ² ≤ <em>y</em> ≤ √<em>x</em>}

So we have

\displaystyle \iint_D x^2(y-x)\,\mathrm dx\,\mathrm dy = \int_0^1 \int_{x^2}^{\sqrt x} x^2(y-x)\,\mathrm dy\,\mathrm dx \\\\ = \int_0^1 \left(\frac{x^2y^2}2-x^3y\right)\bigg|_{y=x^2}^{y=\sqrt x} \\\\ = \int_0^1 \left(\frac{x^3}2-x^{7/2}+x^5-\frac{x^6}2\right)\,\mathrm dx \\\\ = \left(\frac{x^4}8 - \frac{2x^{9/2}}9 + \frac{x^6}6 - \frac{x^7}{14}\right)\bigg|_{x=0}^{x=1} = \frac18-\frac29+\frac16-\frac1{14} = \boxed{-\frac{1}{504}}

5 0
3 years ago
Rosa worked 28 hours this week and was paid $7 per hour. What were her tot earnings for the week?​
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Answer:

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Step-by-step explanation:

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3 years ago
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Oh okie oh gosh lol lol lol is king
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BabaBlast [244]
Unfortunately you have not included the directions.  Are you supposed to solve for x?  or for y?

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4 years ago
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MrRissso [65]

Answer:

4(5x-20)=-20 should be x=3

6 0
3 years ago
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