Answer:
The value of the test statistic and the number of degrees of freedom is 2.148 and 11 respectively.
Step-by-step explanation:
The mean annual tuition and fees for a sample of 12 private colleges was $36,800 with a standard deviation of $5000

n = 12
Claim: You wish to test whether the mean tuition and fees for private colleges is different from $33,700

Since n < 30 and sample standard deviation is given so, we will use t test
Formula : 
Substitute the values in the formula :


Degree of freedom = n-1 = 12-1 =11
So,. Option D is true
Hence the value of the test statistic and the number of degrees of freedom is 2.148 and 11 respectively.