Answer:
8x + 4
Step-by-step explanation:
At x = 0, y-coordinate is at -4 so that means f(0) = -4
Now for f(x) = 4, we need to find any x-coordinates such that y-coordinates is 4.
There are two possible answer: x = -8 and x = 8
So x = -8, 8
Hope this helps.
You can't solve this unless you have numbers to substitute or another equation.
Y = t*e^(-t/2)
y' = t' [e^(-t/2)] + t [e^(-t/2)]' = e^(-t/2) + t[e^(-t/2)][-1/2]=
y' = [e^(-t/2)] [1 - t/2] = (1/2)[e^(-t/2)] [2 - t] = - (1/2) [e^-t/2)] [t -2]
