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Olenka [21]
3 years ago
15

Graphing Do these and you will get brainliest answer!

Mathematics
2 answers:
kompoz [17]3 years ago
6 0

Answer:

y=1

Step-by-step explanation:

il63 [147K]3 years ago
5 0
  • Here the line is parallel to x axis
  • Slope (m) will be tan(0)=0
  • Y intercept is 1.

Y is constant.

The equation of line will be

  • y=0x+1
  • y=1
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Three boys, Adam, Kyle, and Ty, and two girls, Anne and Kate, have volunteered to help plan the school dance. One student will b
Karo-lina-s [1.5K]

Answer:

2:4

Step-by-step explanation: Subtract 1 from total amount then find the number of girls I think sorry

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2 years ago
"find the reduction formula for the integral" sin^n(18x)
dexar [7]
Let

I(n,a)=\displaystyle\int\sin^nax\,\mathrm dx
For demonstration on how to tackle this sort of problem, I'll only work through the case where n is odd. We can write

\displaystyle\int\sin^nax\,\mathrm dx=\int\sin^{n-2}ax\sin^2ax\,\mathrm dx=\int\sin^{n-2}ax(1-\cos^2ax)\,\mathrm dx
\implies I(n,a)=I(n-2,a)-\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx

For the remaining integral, we can integrate by parts, taking

u=\sin^{n-3}ax\implies\mathrm du=a(n-3)\sin^{n-4}ax\cos ax\,\mathrm dx\mathrm dv=\sin ax\cos^2ax\,\mathrm dx\implies v=-\dfrac1{3a}\cos^3ax

\implies\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx=-\dfrac1{3a}\sin^{n-3}ax\cos^3ax+\dfrac{a(n-3)}{3a}\int\sin^{n-4}ax\cos^4ax\,\mathrm dx

For this next integral, we rewrite the integrand

\sin^{n-4}ax\cos^4ax=\sin^{n-4}ax(1-\sin^2ax)^2=\sin^{n-4}ax-2\sin^{n-2}ax+\sin^nax
\implies\displaystyle\int\sin^{n-4}ax\cos^4ax\,\mathrm dx=I(n-4,a)-2I(n-2,a)+I(n,a)

So putting everything together, we found

I(n,a)=I(n-2,a)-\displaystyle\int\sin^{n-2}ax\cos^2ax\,\mathrm dx
I(n,a)=I(n-2,a)-\left(-\dfrac1{3a}\sin^{n-3}ax\cos^3ax+\dfrac{n-3}3\displaystyle\int\sin^{n-4}ax\cos^4ax\,\mathrm dx\right)
I(n,a)=I(n-2,a)-\dfrac{n-3}3\bigg(I(n-4,a)-2I(n-2,a)+I(n,a)\bigg)+\dfrac1{3a}\sin^{n-3}ax\cos^3ax
\dfrac n3I(n,a)=\dfrac{2n-3}3I(n-2,a)-\dfrac{n-3}3I(n-4,a)+\dfrac1{3a}\sin^{n-3}ax\cos^3ax

\implies I(n,a)=\dfrac{2n-3}nI(n-2,a)-\dfrac{n-3}nI(n-4,a)+\dfrac1{na}\sin^{n-3}ax\cos^3ax
7 0
3 years ago
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hichkok12 [17]

Answer:

7

Step-by-step explanation:

3 0
3 years ago
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The stem-and-leaf plot shows kilometers walked by participants in a charity benefit walk. Use it to answer the questions. a. Des
aivan3 [116]

Answer / Explanation

The question is incomplete. It can be found in search engines:

However, kindly find the complete question below:

Question:

The stem and leaf plot shows kilometers walked by participants in a charity benefit walk. Use it to answer the question

12|3 3 6 7 9 9

13| 1 1 4 5 5

14| 0 0 2 3 3 8 8 9

15| 2 2 2 2 2 3 5 5 7

16| 4 5 5 9 9

17|3 5

(a) How many people participated in the walk? Exactly 35 people participated in the walk.

(b)How many of the walkers traveled more than 14 kilometers? About 16-22 people traveled more than 14 kilometers.

Answers:

(a) Exactly 35 people participated in the walk.

(b) About 16-22 people traveled more than 14 kilometers.

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What is the value of the expression x^y+z/z if x = -4, y = 2, and z = 2
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Answer:

17

Step-by-step explanation:

Just ask Siri "What is the expression" then stop and copy-paste the question into the Siri textbox It is that easy.

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