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dmitriy555 [2]
3 years ago
13

An airplane flying from los angeles to NYC losess both engines and all steering controols at 10,000 ft of altatude it falls at a

constant rate of 500 ft per minute medical staff need to know when this plane will crash
Please hurry if you answer ill mark you brainlest!!!
Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

20 min i hope this answers helps u

Step-by-step explanation:

10000÷500=20

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If the starting population of 5 rabbits grows at 200% each year, how many will there be 20 years?
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Using the normal distribution, it is found that there was a 0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 700, \sigma = 50.

The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:

X = 790:

Z = \frac{X - \mu}{\sigma}

Z = \frac{790 - 700}{50}

Z = 1.8

Z = 1.8 has a p-value of 0.9641.

X = 575:

Z = \frac{X - \mu}{\sigma}

Z = \frac{575 - 700}{50}

Z = -2.5

Z = -2.5 has a p-value of 0.0062.

0.9641 - 0.0062 = 0.9579.

0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

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(x-8)^2+(y-2)^2=16
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