Answer : The equilibrium concentrations of are, 0.2646, 0.0584 and 0.0584.
Explanation : Given,
Moles of = 0.323 mole
Volume of solution = 1 L
Initial concentration of = 0.323 M
Let the moles of be, 'x'. So,
Concentration of = x M
Concentration of = x M
The given balanced equilibrium reaction is,
Initial conc. 0.323 M 0 0
At eqm. conc. (0.323-x) M (x M) (x M)
The expression for equilibrium constant for this reaction will be,
Now put all the given values in this expression, we get :
By solving the term 'x', we get :
x = 0.0584
Thus, the concentrations of at equilibrium are :
Concentration of = (0.323-x) M = (0.323-0.0584) M = 0.2646 M
Concentration of = x M = 0.0584 M
Concentration of = x M = 0.0584 M
Therefore, the equilibrium concentrations of are, 0.2646, 0.0584 and 0.0584.