Answer:
D
Explanation:
In the Rb atom the valence electron is farther from its nucleus than the valence electron of Li is from its nucleus
Since the half-life is 4.5 billion years, two half-lives would have elapsed after 9 billion years.
<span>If you start with 400 g, half decays during the first half-life, leaving 200 g. </span>
<span>During the second half-life, half of the 200 g decays, leaving 100 g.</span>
Answer is: 153.52 grams of hypobromous acid <span>must be added.
</span>Chemical dissociation: HBrO ⇄ H⁺ + BrO⁻.
pH = 4.25.
pH = -log[H⁺].
[H⁺] = 10∧(-pH).
[H⁺] = 10∧(-4.25).
[H⁺] = [BrO⁻] = 5.62·10⁻⁵ M.
Ka = [H⁺] · [BrO⁻] / [HBrO].
2.00·10⁻⁹ = (5.62·10⁻⁵ M)² / [HBrO].
[HBrO] = 3.16·10⁻⁹ M² / 2.00·10⁻⁹.
[HBrO] = 1.58 M.
m(HBrO) = n(HBrO) · M(HBrO).
m(HBrO) = 1.58 mol · 96.91 g/mol.
m(HBrO) = 153.52 g.
Actually Welcome to the concept of General organic chemistry.
1.) The formula for alkanes is Cn H2n+2
===> here n = 500, hence we get as,
C500, 2n+2 = 2(500)+2 ==> 1000+2 ==> 1002
hence the formula is ==> C500 H1002
2.) The formula for alkenes is,
CnH2n
hence, here n = 15
so we get as,
===> C15 H30
Answer: A. 0.0375
Explanation:
To calculate the moles :
According to stoichiometry :
As 5 moles of 
give = 2 moles of 
Thus 0.094 moles of give =
of
Thus 0.0375 moles of will be produced when 3.00g of O₂ react completely
