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Gnom [1K]
3 years ago
6

Copper(I) complexes tend to be tetrahedral rather than octahedral or square planar. Why is this the case? Explain your reasoning

.
Chemistry
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

The ion is d^10

Explanation:

Tetrahedral geometry is one in which the central atom/ion is located at the center of four ligands positioned at the corners of a tetrahedron.

It is different from a square planar complex wherein the ligands are positioned at the corners of a square with the central atom/ion at the center of the square.

Tetrahedral complexes are more common with d^10 species.The electronic configuration of Cu I is [Ar]3d104s1. Hence, a tetrahedral geometry is preferred over a square planar geometry.

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4 years ago
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The rate constant is mathematically given as

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<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

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K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

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<h3>Boyle's  Law</h3>

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