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umka21 [38]
3 years ago
15

Perform the indicated operation. Show all necessary work.

Mathematics
2 answers:
alekssr [168]3 years ago
8 0

Answer:

b

Step-by-step explanation:

cus -2-9 is the simpliest number

kvv77 [185]3 years ago
6 0

Answer:

b is the answer ;)) ........................

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What's number is 100,000,000 more than 5,438,724,022
Artist 52 [7]

The answer is, as I see it, 5,538,724,022.

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6 0
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Abc is a triangle
alexandr1967 [171]
I’m pretty sure it is 27.89 cm^2
7 0
3 years ago
Use the table to write a linear function that relates y to x .
nikitadnepr [17]

Answer:

y= -1/4x

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP!!!!
Mazyrski [523]
<h3>Answer:   A.  18</h3>

===========================================================

Explanation:

The set A U B represents the list of items that are either in set A, set B or both sets at the same time. The "U" is the union symbol.

Set A U B looks like this

A U B = {-10, 8, 12, 26, 29,   -8, - 1,5, 26, 36}

I basically started with set A, then tacked on the stuff in set B shown in bold.

From here, we toss out the duplicate item 26 and we can optionally sort the set

A U B = {-10, -8, -1, 5, 8, 12, 26, 29, 36}

We see that the number 18 is not in this final set, which is why choice A is the answer.

--------------------

Put another way: the number 18 is neither in set A nor set B, so it cannot be in set A U B.

Something like -10 is in set A, so it's going to be in set A U B as well. We can rule out choice B for this reason. Choices C and D follow a similar idea as choice B.

4 0
3 years ago
Suppose that the functions p and q are defined as follows.
AlekseyPX
<u>Answer</u>
Part 1 = -441
Part 2 = -539

Explanation
(p.q)(5) = (-2x+1)(2x²-1)
             = (-2x×2x²)-(-2x×1)+(1×2x²)-(1×1)
             = -4x³+2x+2x²-1
             = -4x³+2x²+2x-1
Substituting x witj 5;
-4×5³+2×5²+2×5-1
-441

part 2
(q.p)(5) = (2x²-1)(-2x+1)
            = (2x²×-2x)-(2x²×1)-(1×-2x)+(1×1)
            =  -4x³-2x²+2x+1

Substituting x with 5;
-4×5³-2×5²+2×5+1
-539
4 0
3 years ago
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