I need help with these two problems.
1 answer:
Answer:
the equation is -
Explanation:
Given -
We have to find a line passing through the point nd parallel to the given line.
Find the slope of the given line.
It is the coefficeint of
m₁ = 1
The two lines are parallel. Hence
m₂=m₁=1 Where m₂is the slope of the second line.
You have slope and the points
Find the Y intercept
Y-Intercept and slope m₂=1
Fix the equation
You might be interested in
The correct option A: graph A, shows the logarithmic function;
f(x) = log₃x + 1
<h3>Explain the term logarithmic function?</h3>- The opposite of such an exponential function is a logarithmic function.
- A log function and then an exponential function both use the same base.
- An exponent is a logarithm. f(x) = bx is how the exponential function be expressed.
- The formula again for logarithmic function is f(x) = log base b of x.
f(x) = log₃x + 1
- When x = 1
f(1) = log₃1 + 1
f(1) = 0 + 1
f(1) = 1
(1, 1)
- When x = 3
f(3) = log₃3 + 1
f(3) = 1 + 1
f(3) = 2
(3, 2)
Thus, the graph must contain the points (1, 1), (3, 2).
Therefore, graph A define the given logarithmic function;
f(x) = log₃x + 1.
To know more about the logarithmic function, here
#SPJ4
