Ryan only work for 9 1/4 hour everyday because he takes 1 1/4 hour of break so you minus the from the total and get the sum of 9 1/4
Answer:
I belive x=4.9
Step-by-step explanation:
Answer:
1. d 2. d 3. a
Step-by-step explanation:
1. factor
((w-4)(w-6))/((w-5)(w-6))+8/(w-5)
solve
(w-4)/(w-5)+8/(w-5)
(w+4)/(w-5), so d
2.factor
((b+2)(b-4))((b+2)(b-1))-6/(b-1)
solve
(b-4)/(b-1)-6(b-1)
(b-10)/(b-1), so d
3. (2/5t-3/3t)/(1/2t+1/2t)
(2/5t-1/t)/(2/2t)
(2/5t-1/t)/(1/t)
t(2/5t-1/t)
2/5-1=-3/5, so a
Answer:
Step-by-step explanation:
Given:
u = 1, 0, -4
In unit vector notation,
u = i + 0j - 4k
Now, to get all unit vectors that are orthogonal to vector u, remember that two vectors are orthogonal if their dot product is zero.
If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then
u. v = 0 [<em>substitute for the values of u and v</em>]
=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k) = 0 [<em>simplify</em>]
=> v₁ + 0 - 4v₃ = 0
=> v₁ = 4v₃
Plug in the value of v₁ = 4v₃ into vector v as follows
v = 4v₃ i + v₂ j + v₃ k -------------(i)
Equation (i) is the generalized form of all vectors that will be orthogonal to vector u
Now,
Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e

Where;
|v| = 
|v| = 
= 
This is the general form of all unit vectors that are orthogonal to vector u
where v₂ and v₃ are non-zero arbitrary real numbers.