Hi there!
**Recall that tangent is Opposite / Adjacent**
tan (5π / 6) according to the unit circle equals -1 / √3. We can go through each choice and eliminate:
- tan (-5π / 6) is in the third quadrant which would mean that the value would be positive 1 / √3. This choice is incorrect.
- tan (7π / 6) is the same as tan (-5π / 6), which is positive 1 / √3. This choice is incorrect.
- cot (5π / 6) is the reciprocal of tan 5π / 6, which is incorrect.
- tan (-π / 6) is equal to -1 / √3. This choice is correct.
Therefore, the correct choice is tan (-π / 6).
Use the quadratic formula, x=
(don't know how to type the "-"sign in the formula, so there is only the "+" in the formula)
in this case, a=1, c=34, b is unknown
from the roots, we can tell that -b+
=2(5+3i)=10+6i
Note: the original equation already give b as -b, so -(-b)=10, b=10
using b^2-4ac=(6I)^2,
b^2-4*34=-36
b^2=100
you will also get b=10
Answer:
48.48%
Step-by-step explanation:
Let's assume that there is a number N of women.
32% of these are smokers, then there are 0.32*N smokers
then 68% of these are non-smokers, then there are 0.68*N non-smokers.
Let's assume that the probability of having a ectopic pregnancy for a non-smoker is p (and the probability for a smoker will be 2*p)
Then the number of women with an ectopic pregnancy that are non-smokers is:
p*0.68*N
The number of women with an ectopic pregnancy that are smokers is:
2*p*0.32*N
Then the total number of women with an ectopic pregnancy will be:
p*0.68*N + 2*p*0.32*N
The percentage of women having an ectopic pregnancy that are smokers is equal to the quotient between the number of women with an ectopic pregnancy that are smokers and the total number of women with an ectopic pregnancy, all that times 100%.
The percentage is:
Taking p and N as common factors, we get:
Then we get:
16,000 paid
8 years passed
12,000 returned
-4000 difference
-4000/16,000 x 100%
-25% (Answer)
Less than as .25<.4 ......
