Question

A college is selling tickets for a winter fund-raiser. One day, Krissa sold 14 adult tickets and 8 student tickets for a total of $376. The next day, she sold 7 adult tickets and 11 student tickets for a total of $272. Krissa wanted to find the price of one adult ticket, a, and the price of one student ticket, s. She wrote and solved the following system of equations.

Answer 1

Answer:

Step-by-step explanation:

Let's solve this by elimination, then substitution.

x= Adult ticket

y= Student ticket

First day: 14x + 8y = 376

Second day: 7x + 11y = 272:

14x+8y=376

7x+11y=272

Divide 14x+8y=376 by -2:

-7x+-4y=-188

7x+11y=272

Eliminate both -7x and 7x:

-4y=-188

11y=272:

Add all numbers:

7y=84

Divide both sides by 7/ divide 84 by 7:

y=12

Now substitute y into one of the equations:

7x+11y=272:

7x+11(12)=272

Simplify:

7x+132=272

Subtract both sides by 132:

7x=140

Divide both sides by 7 (140/7):

x=20

Adult Tickets: $20

Student Tickets: $12