Answer:
P-value = 0.009997
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 24
Nature of test: One-tailed test(Left tailed test)

We have to calculate the p-value.
Degree of freedom = n - 1 = 23
We calculate the p-value from the table corresponding to t score -2.50 and degree of freedom 23.
P-value = 0.009997
0.009997 is the probability of a value being to the left of a number that has a student-t statistic of –2.50.
Begin making a chart of each car per hour. answer: 2hours
1.0.583333333332. 0.043.1
Answer:
The sigma notation would look like this:
∞
Σ 48(1/4)^i-1
i = 1
Step-by-step explanation:
I can't seem to find a good way to make it more connected so I'll just have to tell you. The ∞ is above the ∑, while the i = 1 is under it. That is all one thing. The rest is followed as normal, and it is all next to the ∑
9514 1404 393
Answer:
![\left[\begin{array}{cc|c}1&0&2\\0&2&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%260%262%5C%5C0%262%262%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The system of equations can be written in standard form as ...
x + 0y = 2
0x +2y = 2
The augmented matrix representation of these is ...
![\left[\begin{array}{cc|c}1&0&2\\0&2&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%260%262%5C%5C0%262%262%5Cend%7Barray%7D%5Cright%5D)