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3 years ago

HELPPP PLEASE I GIVE BRAINLIEST

Mathematics

1 answer:

Tresset [83]3 years ago

4 0

Answer:

3 1/2

Step-by-step explanation:

3/7 = 0.429

1/2 = 0.5

Hopefully this helps!

Brainliest please?

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some kids like to ride their bikes to and from school let d be the distance in miles from a kid home to school write 2 expressio

Nesterboy [21]

Expression 1; If your friend bikes 1.5 miles home from school each day for 4 weeks, they bike a total of - miles in that time period. The math I did was multiply 5 by 4 to get 20 school days in 4 weeks, and multiplied 1.5 by 20 to get 30 miles biked in 4 weeks.
Expression 2; If you bike 3.25 miles home from school each day, using the same math shown in the previous expression, substituting 1.5 for 3.25. Using that math, you would bike 65 miles in 4 weeks.

Sarcastic conclusion; You and your friend both get quite the leg day just to get home from school!

5 0

4 years ago

Solve a real world problem that can be represented by the expression (-3)(5)+10

vovikov84 [41]

Using PEMDAS you start with parenthesis

(-3)(5) = -3 x 5 = -15

-15 + 10 = -5

The answer is -5

6 0

3 years ago

Write a system of equations and then solve by the method of your choice. Reserved seat tickets for the football game cost $4.00

amid [387]

Given :

Reserved seat tickets for the football game cost $4.00 each and general admission tickets cost $3.00 each.

After the game is over, the turnstile count shows 1787 people attended the game. The total receipts were $5792.

To Find :

The number of each general admission tickets sold.

Solution :

Let, general admission are x.

So, Reserved seat tickets will be 1787 - x.

Now, total amount T = 3x + 4( 1787 - x )

T = $5792

3x + 4( 1787 - x ) = $5792

-x + 7148 = 5792

x = 1356

Therefore, the number of each general admission tickets sold are 1356.

Hence, this is the required solution.

7 0

4 years ago

If MH = 18cm and HA = 29cm, what is MA?

Murrr4er [49]

Answer:

<h2>The leg MA measures 22.7 centimeters.</h2>

Step-by-step explanation:

Assuming that's about a right triangle, the image attached shows a representation of this problem.

We use the Pythagorean Theorem to find the missing leg, which we are gonna call $y$

$29^{2} =18^{2}+y^{2}\\y^{2}=29^{2}-18^{2}\\y=\sqrt{841 - 324} \approx 22.7 \ cm$

Therefore, the leg MA measures 22.7 centimeters.

4 0

3 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

7 0

3 years ago