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kozerog [31]
3 years ago
9

Write an equation of the line in slope-intercept form. JY 1 (3, 3) (0, 2) 2 4y=​

Mathematics
1 answer:
stellarik [79]3 years ago
3 0

Correct answer: y = \frac{1}{3}x + 2

To find out the slope, you would need to remember this slope formula: \frac{y_{2}-y_{1}}{x_{2}-x_{1}}. We can use the two points provided on the graph to figure out the slope. We can label (3, 3) as x_{1} and y_{1}, and (0, 2) as x_{2} and y_{2}. Now we can plug these numbers into the slope formula to find out the slope:

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} → \frac{2-3}{0-3} → \frac{-1}{-3} → \frac{1}{3}

To find out the y-intercept, just substitute (3, 3) into the slope-intercept<em> </em>formula ( <em>y = mx + b</em> ) with the slope that is substituted for '<em>m</em>' that we already solved earlier.

y = mx + b

(3) = \frac{1}{3}(3) + b

3 = 1 + b

2 = b

You can also prove this true by looking at the graph provided. The line intersects at the y-axis at 2.

Now we know that m = \frac{1}{3} and b = 2, we can substitute it into the slope-intercept formula. Thus, the answer is y = \frac{1}{3}x + 2.

Hope this helps you! Let me know if you have any more questions related to this problem.

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Solve the following recurrence relation: <br> <img src="https://tex.z-dn.net/?f=A_%7Bn%7D%3Da_%7Bn-1%7D%2Bn%3B%20a_%7B1%7D%20%3D
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By iteratively substituting, we have

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and the pattern continues down to the first term a_1=0,

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Recall the formulas

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Answer:

a_n=5-2(n-1), all integers where n≥1

Step-by-step explanation:

we know that

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a_n is the th term

a_1 is the first term

d is the common difference

n is the number of terms

we have

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Remember that

In an Arithmetic Sequence the difference between one term and the next is a constant, and this constant is called the common difference.

To find out the common difference subtract the first term from the second term

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substitute the given values in the formula

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Airida [17]
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