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2 years ago

6-y-x^2 use x=5 and y=4

Mathematics

1 answer:

Ulleksa [173]2 years ago

5 0

Answer:

6 - 4 - 5 ^ 2 = -23

hope this helps

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IF P(A)=1/3, P(B)=2/5, and P(AuB)=3/5, what is P(A^B)?

Bumek [7]

The probability of the union of two events is the sum of their probability, minus the probability of their interserction:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

If we plug the known values into this formula, we have

$\dfrac{3}{5} = \dfrac{1}{3} + \dfrac{2}{5} - P(A\cap B)$

From which we can deduce

$P(A\cap B) = \dfrac{1}{3} + \dfrac{2}{5} - \dfrac{3}{5} = \dfrac{2}{15}$

So, the probability of $A \setminus B$ is a bit less than $P(A)$ , we have to take away all events that belong to B as well:

$P(A \setminus B) = P(A) - P(A\cap B) = \dfrac{1}{3} - \dfrac{2}{15} = \dfrac{1}{5}$

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Bogdan [553]

Answer:

Step-by-step explanation:

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2 years ago

The data below gives the number of speeding tickets given per day at a certain location on a highway over a two-week period.

kramer

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2 years ago

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Answer:

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2 years ago

Write an exponential equation that represents the given situation. You invest $1000 and it increases 12% each year. Can you teac

IrinaK [193]

Answer:

FV= 1,000*(1.12^n)

Step-by-step explanation:

Giving the following information:

Initial investment= $1,000

Increase rate= 12% = 0.12

We need to formulate an exponential equation to show the value in n years.

<u>To calculate the Future Value, we need to use the following formula:</u>

FV= PV*(1+i)^n

Being:

FV= Future Value

PV= Initial Investment

i= increase rate

n= number of periods

FV= 1,000*(1.12^n)

<u>For example, for one year:</u>

FV= 1,000*(1.12^1)

FV= $1,120

For 3 years:

FV= 1,000*(1.12^3)

FV= $1,404.93

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