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andreev551 [17]
3 years ago
12

Which set of side lengths form a right triangle?

Mathematics
1 answer:
astraxan [27]3 years ago
4 0
Since we don't want to use the Pythagorean Theorem on all of these, first we look for some Pythagorean Triples. Its very helpful to know some of the common ones, so here's a list:

3, 4, 5
5, 12, 13
7, 24, 25
8, 15, 17

So we either look for these or a multiple of these numbers.

The last one is the only one that fits because 15, 20, 25 is a multiple of the triple 3, 4, 5 by multiplying all of them by 5. 

Thus, 15, 20, 25 forms a right triangle. 
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Explain the difference between parallel and perpendicular slope in fewer than twenty words.
viva [34]

Answer:

parallel refers to two equidistant lines, Because the lines are equally distant, they have the same slope and the angle between them is zero. On the other hand, when two lines intersect at a right angle, they are called perpendicular.

Step-by-step explanation:

7 0
3 years ago
Can anyone help me ?
nydimaria [60]

Which TWO expressions are equivalent to<em> </em><em>(x - y) </em>2/3 - 3/4 <em>(y-x)</em>

8 0
3 years ago
What is the perimeter, to the nearest hundredth of a unit, of the the
AnnyKZ [126]

Answer:

20.31 units to the nearest hundredth.

Step-by-step explanation:

We need to use the distance formula between the points and find their sum.

D1 = √((2-2^2 + (1+3)^2)  = √16 = 4

D2 =  √(-1-2)^2 + (3-1)^2) = √13

D3 = √(-3+1)^2 + (0-3)^2) =  √13

D4 = √(-3+3)^2 + (-4)^2) = √16 = 4.

D5 = √(-3-2)^2 + (-4+3)^2) = √26.

Perimeter = D1+D2+D3+D4+D5

=  4+√13+√13 + 4 +√26

= 20.31 units.

4 0
3 years ago
The cabinet that will enclose the Acrosonic model D loudspeaker system will be rectangular and will have an internal volume of 2
Kazeer [188]

Answer:

Dimensions of cabinet

x (wide) = 1.93 ft

y (hight) = 2.895 ft

p (depth) =0.43 ft

Step-by-step explanation:

Dimensions of cabinet

y  height

x  wide

p  deph

From problem statement

y = 1.5 x       V = y * x * p      V = 1.5*x²p      but p = V/y*x     p = 2.4/1.5 x²

p = 1.6 / x²

Then

Area of top and bottom    A₁ = 2*x*p  ⇒   2*x*1.6/x²  

A₁  = 3.2 /x

And cost  in $ C₁  = 0,9 * 3.2 /x     ⇒   C₁  = 2.88/x

Area of sides (front and rear not included)

A₂ = 2*y *p      A₂ = 3*x*1.6/x²    A₂ = 4.8/x

And cost in $ C₂ = 0.9 * 4.8 /x    C₂ = 4.32 /x

Area of  front and rear   A₃  =2* y*x    A₃  = 2*1.5 *x²    A₃ = 3x²

And cost  C₃ = 0.3 * 3/x²    =  0.9/x²

Total cost  C(x) = C₁  + C₂ + C₃            C(x) = 2.88/x  +  4.32/x + 0.9x²

Taking derivatives

C´(x)  =  -2.88/x² - 4.32 /x² + 0.9 x

C´(x) = 0             -2.88/x² - 4.32/x² + 0.9 x = 0     -2.88 - 4.32 + 0.9 x³ = 0

-7.2 + x³ = 0    x³ = 7.2    

x = 1.93 ft        y = 1.5*1.93  = 2.895 ft    and p = 0.43 ft

               

4 0
3 years ago
Find the standard equation of the circle
Tpy6a [65]
(x - h) 2<span> + (y - k) 2</span><span> = r2,</span><span>  is the standard equation of a circle</span>
6 0
3 years ago
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