Since we don't want to use the Pythagorean Theorem on all of these, first we look for some Pythagorean Triples. Its very helpful to know some of the common ones, so here's a list:
3, 4, 5 5, 12, 13 7, 24, 25 8, 15, 17
So we either look for these or a multiple of these numbers.
The last one is the only one that fits because 15, 20, 25 is a multiple of the triple 3, 4, 5 by multiplying all of them by 5.
This would be a guess but I think you would need two numbers in the hundreds that also have 2 parts of which have a product of a number ending in 0, like 4 and 5.
Before the fraction: -1/2, i have a negative sign use y=mx+b 3=-1/2(2)+b 3+1=-1+b+1 4=b check your work 0=-1/2x+4 0+4=-1/2x (4)÷(-1/2)=(-1/2x)÷(-1/2) -2=x another pair is (-2,0) use this to figure out the other points, and/or the points you have in the multiple choice.
