Answer:
(4.75, 2.25)
Step-by-step explanation:
Given the coordinate (x,y). If this coordinate is reflected over the x axis, the resulting coordinate will be (x, -y)
Note that the y coordinate was negated.
Let the original point needed be (x, y)
If the new point is located at (4.75, -2.25)
Since the y coordinate was negated, then;
-y = -2.25
y = 2.25
x = 4,75 (x coordinate remains the same)
Hence the original point is (4.75, 2.25)
Answer:
Probability that their mean credit card balance is less than $2500 is 0.0073.
Step-by-step explanation:
We are given that a bank auditor claims that credit card balances are normally distributed, with a mean of $3570 and a standard deviation of $980.
You randomly select 5 credit card holders.
Let<em> </em>
<em> = </em><u><em>sample mean credit card balance</em></u>
The z score probability distribution for sample mean is given by;
Z =
~ N(0,1)
where,
= population mean credit card balance = $3570
= standard deviation = $980
n = sample of credit card holders = 5
Now, the probability that their mean credit card balance is less than $2500 is given by = P(
<em> </em>< $2500)
P(
<em> </em>< $2500) = P(
<
) = P(Z < -2.44) = 1 - P(Z
2.44)
= 1 - 0.9927 = 0.0073
The above probability is calculated by looking at the value of x = 2.44 in the z table which has an area of 0.9927.
Therefore, probability that their mean credit card balance is less than $2500 is 0.0073.
Answer:
you divide the top number by the bottom number
Step-by-step explanation:
2/5 = 0.4
Answer: 1/18
Step-by-step explanation:
9 total marbles
2 red
so the first time he picks it would be a 2/9 chance of the marble being red
the second time there would be 8 total marbles and 2 red, so it would be a 2/8 or 1/4 chance.
the probability is found by doing 2/9*1/4 which equals 2/36 or 1/18.
A discrete variable is a variable which may take only certain discrete values; for example the number of people in a household is a discrete variable which may have the value 1, 2, 3, etc. but cannot have intermediate values such as 1.473 or 3.732.
Choice d) can be represented by a discrete probability distribution, the other choices cannot be so represented.