Question

Write an equation for a line perpendicular to y = -5x – 4 and passing through the point (15,5)

Answer 1

The equation for the line in point-slope form that passes through (15, 5) and is perpendicular to $y = -5x - 4$ is $\mathbf{y -5 = \frac{1}{5} (x - 15)}$

Recall:

The equation of the line can be written in point-slope form (y - b = m(x - a)) and also in slope-intercept form (y = mx + b).

Given:

• the point the line passes through: (15, 5)
• the line it is perpendicular to: y = -5x - 4

Find the slope (m):

The slope value will be the negative reciprocal of the slope value of y = -5x - 4.

• The slope of y = -5x - 4 is -5.

• Therefore, the slope of the line perpendicular to y = -5x - 4 will be the negative reciprocal of -5 which is: 1/2.

Write the equation in point-slope form by substituting m = 1/2 and (a, b) = (15, 5) into y - b = m(x - a)

• Thus:

$y -5 = \frac{1}{5} (x - 15)$

Therefore, the equation for the line that passes through (15, 5) and is perpendicular to $y = -5x - 4$ is $\mathbf{y -5 = \frac{1}{5} (x - 15)}$

Learn more here:

brainly.com/question/11624671