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2 years ago

What is the first step to simplify the equation 152 – 12x +7=4

Mathematics

1 answer:

Aleks04 [339]2 years ago

6 0

Isolate the variable by dividing each side by factors that don't contain the variable.

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Ms. Skeen bought 3 pounds of candy for the Christmas party. There was a total of 147 pieces of candy. She wants to divide it amo

ohaa [14]

The 3 lbs of candy is irrelevant, so we can discard that. All you need to do is divide 147 by 26, which is 5.65 pieces of candy. Each student will get 5 pieces, with a few left over.

5 0

3 years ago

If OP = 15 r = 1/3 what is OP

svp [43]

The answer would be 72

8 0

2 years ago

Read 2 more answers

BRAINLIESTT ASAP! PLEASE HELP ME :)

Oduvanchick [21]

Answer:

$\displaystyle symmetric$

Step-by-step explanation:

Everything is distributed evenly on both ends.

I am joyous to assist you anytime.

8 0

3 years ago

Can anybody help me with this this is all I need for today and it is for a grade. PLEASE HELP

zzz [600]

Not proportional, because the 185 divided by three isn’t 65. However, the others were 65 so it wasn’t consistent.

The constant would be 65.

4 0

3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

8 0

3 years ago