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Vinil7 [7]
3 years ago
11

PLS HURRY DOUBLE-CHECKINGwhat is: 94 ÷ 17​

Mathematics
2 answers:
maxonik [38]3 years ago
8 0

Answer:

94/17=5.5294

Step-by-step explanation:

that's what I got

sergejj [24]3 years ago
7 0
Answer: 5.529411764705882

I use the calculator to check if that’s correct or not but this is my answer but if you were to round it then it would be, 5.5 or 6 I don’t know but have a good day!!
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You're conducting a significance test for H0 : p = .35, Ha : p < .35. In a sample of size 40, you identify a count of 11 succ
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Answer: c. –1 and .1587

Step-by-step explanation:

As per given , we have

Null hypothesis : H_0 : p= 0.35

Alternative hypothesis :  H_1 : p< 0.35

Since Alternative hypothesis is left-tailed ,so the test must be a left tailed test .

Z -Test statistic for proportion = z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

, where p= population proportion

\hat{p} = sample proportions

n= Sample size.

Let x be the number of successes.

For n= 40 and x= 11

\hat{p}=\dfrac{x}{n}=\dfrac{11}{40}=0.275

Then ,  z=\dfrac{0.275-0.35}{\sqrt{\dfrac{0.35(1-0.35)}{40}}}

z=\dfrac{-0.075}{\sqrt{0.0056875}}

z=\dfrac{-0.075}{0.075415515645}

z=-0.99449031619\approx-1

By using z-table ,

P-value for left-tailed test = P(z<-1)= 1-P(z<1)    [∵ P(Z<-z)= 1-P(Z<z) ]

= 1-0.8413

=0.1587

Hence, the -score and P-value are  <u>–1 and 0.1587</u> .

So the correct option is c. –1 and .1587

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