Say that taking a quarter of student out of the group will add a quarter present of days for food so by take 20 students out you’ll get 60 days (that’s what I got hope this helps)
Four is greater than y, and -1 is less than y
6a - (b - (3a - (2b + c + 4a - (a + 2b - c))))
6a - (b - (3a - (2b + c + 4a - a - 2b + c)))
6a - (b - (3a - (2b - 2b + 4a - a + c + c)))
6a - (b - (3a - (3a + 2c)))
6a - (b - (3a - 3a - 3c))
6a - (b - 3a + 3a + 3c)
6a - (b + 3c)
6a - b - 3c
x³ + x² - 25x - 25
x²(x) + x²(1) - 25(x) - 25(1)
x²(x + 1) - 25(x + 1)
(x² - 25)(x + 1)
(x² - 5x + 5x - 25)(x + 1)
(x(x) - x(5) + 5(x) - 5(5))(x + 1)
(x(x - 5) + 5(x - 5))(x + 1)
(x + 5)(x - 5)(x + 1)
36x² + 60x + 25
36x² + 30x + 30x + 25
6x(6x) + 6x(5) + 5(6x) + 5(5)
6x(6x + 5) + 5(6x + 5)
(6x + 5)(6x + 5)
(6x + 5)²
Answer:
A. is incorrect. He has to divide 76 by 19, instead of subtracting 19 to 76.
B. This equation has one solution. v=4
Step-by-step explanation:
Hi, Martin’s answer is incorrect.
A. He has to divide 76 by 19, instead of subtract 19 to 76.
The correct steps are:
19v = 76
Since 19 is multiplying the variable, to eliminate it we have to divide by 19.
v = 76/19
v = 4
B. This equation has one solution. It’s v=4
Feel free to ask for more if needed or if you did not understand something.
Answer:
(2n+6)^2
Step-by-step explanation:
To solve this, you can use the given formula: x^2 + 2xy + y^2
In this case, 4n^2 is x^2, 24n is 2xy, and 36 is y^2. The next step is:
(2n)^2 + 2(2n)(6) + (6)^2
Since this equation fits into this formula ( x^2 + 2xy + y^2), we can do:
(2n+6)(2n+6) =
(2n+6)^2
Hence, the answer is (2n+6)^2
