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kotykmax [81]
2 years ago
15

Find the volume of a cone with a height of 12 and a base diameter of 6.

Mathematics
1 answer:
vichka [17]2 years ago
5 0

Answer: 466.56

Step-by-step explanation:

Volume = pi times radius^2 times height/3

Radius = 1/2 of the diameter

Volume = 3.24 times 6^2 times 12/3

Volume = 3.24 times 36 times 4

Volume = 116.64 times 4

Volume = 466.56

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The function LaTeX: f\left(x\right)=-x^2+4f ( x ) = − x 2 + 4 defined on the interval LaTeX: -8\le x\le8− 8 ≤ x ≤ 8 is increasin
enyata [817]

Given:

The function is

f(x)=-x^2+4

It defined on the interval -8 ≤ x ≤ 8.

To find:

The intervals on which the function is increasing and the interval on which decreasing.

Step-by-step explanation:

We have,

f(x)=-x^2+4

Differentiate with respect to x.

f'(x)=-(2x)+(0)

f'(x)=-2x

For turning point f'(x)=0.

-2x=0

x=0

Now, 0 divides the interval -8 ≤ x ≤ 8 in two parts [-8,0] and [0,8]

For interval [-8,0], f'(x)>0, it means increasing.

For interval [0,8], f'(x)<0, it means decreasing.

Therefore, the function is increasing on the interval [-8,0] and decreasing on the interval [0,8].

7 0
3 years ago
Please help<br><br> Boats A, B, C, and D are all the same distance from Boat O.
BlackZzzverrR [31]

Answer:

α = 62°

β = 56°

gamma = 90°

Step-by-step explanation:

ΔAOB is isosceles, so m∠A = m∠ABO = 28

28 + 28 + m∠AOB = 180

m∠AOB = 180 - 28 - 28 = 124

β = 180 - 124 = 56

arcAB = 124

ΔBOC is isosceles.  α = m∠BCO = 1/2(arc AB) = 1/2(124) = 62

∠D is inscribed in a semicircle

m∠D = gamma = 90°

7 0
2 years ago
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