Plug in 2 for t.
=> -16*(2^2) +80*2 +3
=> -16*4 +160 +3
=> -64+163
=> 99
These could be be some of the answers to the problem. 6:3, 12:6, and 36:18
Answer:
$3628.24
Step-by-step explanation:
we use the formula for accrued value (A) with compounded interest:
![A=P(1+\frac{r}{n})^{n*t}](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bn%2At%7D)
where A= accrued value (principal plus the accumulated interest)
P = principal -> in our case $6000
r = annual interest rate (in decimal form) -> in our case 0.06
n = number of compoundings per year. In our case 2 (semiannually)
t = time in years -> in our case 8
![A=P(1+\frac{r}{n})^{n*t}\\A = 6000(1+\frac{0.06}{2})^{16}\\ A= 6000(1+0.03)^{16}\\A = $9628.24](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bn%2At%7D%5C%5CA%20%3D%206000%281%2B%5Cfrac%7B0.06%7D%7B2%7D%29%5E%7B16%7D%5C%5C%20A%3D%206000%281%2B0.03%29%5E%7B16%7D%5C%5CA%20%3D%20%249628.24)
Since this is the value of principal plus accumulated interest, we subtract from it the principal ($6000) to get the value of just the interest:
$9628.24 - $6000 = $3628.24
Answer:
Step-by-step explanation:
(1). A = π r²
A = 4 π
Area of shaded region is
=
or
(2). C = 4 π
In this case, the length of the bigger arc and the area of shaded region happen to be the same.
The length of the arc ADB is
or
Answer:
Try this
Step-by-step explanation:
So what you have to do is turn 65% into a decimal. 65% as a decimal is 0.65.
Then what you want to do is divide 5.00 and 0.65 and see what you get.