Answer:YES
Step-by-step explanation:
Answer:
Depends on the domain and the graph.
Step-by-step explanation:
Answer:
no mode
Step-by-step explanation:
Mode is the most common number shown therefore....
since there are no numbers repeated, the answer is no mode
Consider the contrapositive of the statement you want to prove.
The contrapositive of the logical statement
<em>p</em> ⇒ <em>q</em>
is
¬<em>q</em> ⇒ ¬<em>p</em>
In this case, the contrapositive claims that
"If there are no scalars <em>α</em> and <em>β</em> such that <em>c</em> = <em>α</em><em>a</em> + <em>β</em><em>b</em>, then <em>a₁b₂</em> - <em>a₂b₁</em> = 0."
The first equation is captured by a system of linear equations,

or in matrix form,

If this system has no solution, then the coefficient matrix on the right side must be singular and its determinant would be

and this is what we wanted to prove. QED
the area of a square = length*length =3a*3a=9a^2