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allochka39001 [22]
2 years ago
13

Maths a²(5a - 3b) -3a²​

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
4 0

Answer:

5a^{3} - 3a^{2} b-3a^{2}

Step-by-step explanation:

a^{2} (5a-3b)-3a^{2} |

Expand brackets

5a^{3} - 3a^{2} b-3a^{2}

Final Answer is

5a^{3} - 3a^{2} b-3a^{2}

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What is the value of X plz help
Tema [17]

Answer:

x = 16

Step-by-step explanation:

(5x + 12)° + (6x - 8)° = 180°

(5x + 12 + 6x - 8)° = 180°

(11x + 4)° = 180°

11x + 4 = 180

11x = 180- 4

11x = 176

x = 176/11

x = 16

5 0
2 years ago
Subtract and simplify. Show work please!
ra1l [238]

1) Final expression: +7y^2-6y-17

2) Final expression: 21x^3-46x^2+59x-30

Step-by-step explanation:

1)

The first expression is

(-2y^2-11y-7)-(-9y^2-5y+10)

First, we remove the 2nd bracket by changing the sign of all the terms inside:

-2y^2-11y-7-+9y^2+5y-10

Now we group the terms with same degree together:

(-2y^2+9y^2)+(-11y+5y)+(-7-10)

Now we solve the expression in each brackets:

(-2y^2+9y^2)+(-11y+5y)+(-7-10)=\\+7y^2-6y-17

So, this is the final expression.

2)

The second expression is

(7x-6)(3x^2-4x+5)

We apply the distributive property, so we rewrite the expression as follows:

(7x-6)(3x^2-4x+5)=7x(3x^2-4x+5)-6(3x^2-4x+5)

Solving both brackets,

7x(3x^2-4x+5)-6(3x^2-4x+5)=\\21x^3-28x^2+35x-18x^2+24x-30

Now we group terms of same degree together:

21x^3-28x^2+35x-18x^2+24x-30=\\21x^3+(-28x^2-18x^2)+(35x+24x)-30

And solving each bracket,

21x^3+(-28x^2-18x^2)+(35x+24x)-30=\\21x^3-46x^2+59x-30

So, this is the final expression.

Learn how to simplify expressions:

brainly.com/question/7014769

brainly.com/question/11007572

brainly.com/question/11334714

#LearnwithBrainly

3 0
3 years ago
Relay races called for 8 people on a team. There were 43 men and 34 women who wanted to race. How many teams could be formed ?ho
ELEN [110]

It would be an odd number of teams. What I did was add 43 and 34 together. Which gave me 77. So 77 people total wanted to race. There can only be 8 racers on each team. Each means to divide.  So I divided 8 and 77. It gave me 9 with a remainder of 5. So there will e 9 teams and 5 racers left out. (:

4 0
2 years ago
Which of the following inequalities is correct?
almond37 [142]

Answer:

A

Step-by-step explanation:

because there variables represent 1 so 1 cant be bigger than one and the other two have real equations

6 0
2 years ago
Los divisores de 100 son tambien divisores de 50 ?
sergiy2304 [10]

Answer:

La afirmación es falsa, no todos los divisores de 100 son divisores de 50, ya que solo se toman en cuenta sus divisores comunes, los cuales son todos los divisores de 50. Expresamos a 100 en sus factores primos: 100 = 2 · 2 · 5 · 5 = 2² · 5² Divisores de 100: {1, 2, 4, 5, 10, 20, 25, 50, 100}

Step-by-step explanation:

8 0
2 years ago
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