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djverab [1.8K]
2 years ago
7

What is the property of (4 + 7) + 8 = 4 + (7 +8) ?

Mathematics
1 answer:
nasty-shy [4]2 years ago
4 0

Answer:

Commutative

Step-by-step explanation:

2 + 4 = 4 + 2 as an example

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Th answer is 5 because 31% of 15 is 4.65
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3 years ago
Among 8 PS4s, four are good and four have defects. Unaware of this, a customer buys 5 PS4s.
astraxan [27]

Answer:

(a) The probability of exactly 2 defective PS4s among them is 0.3125.

(b) The probability that exactly ​ 2 are defective given that  ​at least ​ 2 purchased PS4s are defective is 0.3846.

Step-by-step explanation:

Let <em>X</em> = number of defective PS4s.

It is provided that 4 PS4s of 8 are defective.

The probability of selecting a defective PS4 is:

P(X)=p=\frac{4}{8}=0.50

A customer bought <em>n</em> = 5 PS4s.

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(a)

Compute the probability of exactly 2 defective PS4s among them as follows:

P(X=2)={5\choose 2}(0.50)^{2}(1-0.50)^{5-2}=10\times0.25\times0.125=0.3125

Thus, the probability of exactly 2 defective PS4s among them is 0.3125.

(b)

Compute the probability that exactly ​ 2 are defective given that  ​at least ​ 2 purchased PS4s are defective as follows:

P(X=2|X\geq 2)=\frac{P(X=2\cap X\geq2)}{P(X\geq2)} =\frac{P(X=2)}{P(X\geq 2)}

The value of P (X = 2) is 0.3125.

The value of P (X ≥ 2) is:

P(X\geq 2)=1-P(X

Then the value of P (X = 2 | X ≥ 2) is:

P(X=2|X\geq 2)=\frac{P(X=2)}{P(X\geq 2)}=\frac{0.3125}{0.8125} =0.3846

Thus, the probability that exactly ​ 2 are defective given that  ​at least ​ 2 purchased PS4s are defective is 0.3846.

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3 years ago
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